Question

我试图使用所描述的属性方法git gc 但它不被承认。方法关键也不被认可。

我错过了静态导入吗？

我的代码：

MvcResult result = mockMvc.perform(post(URL_PREFIX + "/scripts/")
     .contentType(MediaType.APPLICATION_JSON)
     .content(asJsonString(script)))
     .andExpect(status().is(HttpStatus.CREATED.value()))
     .andExpect(content().contentTypeCompatibleWith(MediaTypes.HAL_JSON))
     .andDo(document("create-script-example"
     , links(
        linkWithRel("self").description("Link self"),
        linkWithRel("script").description("Link to the created script resource")),
     responseFields(
        attributes(
           key("title").value("Fields for user creation")),
        fieldWithPath("_links").description("The available links"),
        fieldWithPath("name").description("the name of the created script"),
        fieldWithPath("domain").description("the domain of created the script").optional(),
        fieldWithPath("script").description("the code in Groovy format of the created script"))
     , requestFields(
       fieldWithPath("id").description("the id of the script to create, should be null"),
       fieldWithPath("name").description("the name of the script to create"),
       fieldWithPath("domain").description("the domain of the script to create"),
       fieldWithPath("script").description("the code in Groovy format of the script to create")
)))
.andReturn();

Answer 1

我找到了答案： import static org.springframework.restdocs.snippet.Attributes.attributes; import static org.springframework.restdocs.snippet.Attributes.key;

Spring Rest docs属性

1 个答案: