我正在与haystack + Whoosh和DJango合作建立一个基本的搜索引擎。我想要做的是我的每个搜索结果都会有一个＆＃34;收藏夹＆＃34;值（默认为0）。我希望按这个整数对这些结果进行排序，结果是收藏夹数量较多。我已经按照Haystack教程的指南进行了操作，并查找了有关该主题的其他答案，但我似乎无法让它工作。
我的models.py看起来像这样：
class Recipe(models.Model):
primary_url = models.CharField(max_length=500, null=False, blank=False, primary_key=True)
title = models.CharField(max_length=500)
favourite_count = models.IntegerField(null=False, default= 0)
def __unicode__(self):
return self.title
在我的search_indexes.py中，我给了“收藏夹”属性这样的名字：
class RecipeIndex(indexes.SearchIndex, indexes.Indexable):
text = indexes.CharField(document=True, use_template=True)
favourite_count = indexes.IntegerField(model_attr='favourite_count', stored=True)
def get_model(self):
return Recipe
def index_queryset(self, using=None):
#Used when entire index for model is updated
return self.get_model().objects.all()
最后我的urls.py设置如下：
sqs = SearchQuerySet().order_by('-favourite_count')
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^search/', search_view_factory(view_class=views.mySearchView, template='search/search.html', searchqueryset=sqs, form_class=views.myModelSearchForm))
] + static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)
尽管如此，我的结果仍未正确排序。尽管我努力，它们仍然是随机的。我知道urls.py正在理解我对sqs的声明，因为如果我拼写错误就会抛出错误：
KeyError: "No field named 'favrite_count'"
修改
这是views.mySearchView（）
class mySearchView(SearchView):
def __call__(self, request):
"""
Generates the actual response to the search.
Relies on internal, overridable methods to construct the response.
"""
self.request = request
self.form = self.build_form()
#print(self.get_query())
querywords = self.get_query().split()
resultwords = [word for word in querywords if word.lower() not in stopwords]
result = ' '.join(resultwords)
#print(result)
self.query = result
self.results = self.get_results()
return self.create_response()
def get_results(self):
"""
Fetches the results via the form.
Returns an empty list if there's no query to search with.
"""
#sortedQuerySet = sorted(self.form.search(), key=token_similarity)
#return sortedQuerySet
return self.form.search()
def extra_context(self):
request = self.get_query()
if request is not None and not "":
related_recipes = []
words = request.split(' ')
if(len(words) > 1):
for word in words:
temp_list = SearchQuerySet().auto_query(word)[:8]
for obj in temp_list:
if str(self.query).lower() not in str(obj.object.title).lower():
#print(str(self.query).lower()+" is not in "+ str(obj.object.title).lower())
#print('here')
if obj.object.primary_image_url != "test_url":
related_recipes.append(obj)
if len(related_recipes) >= 8:
break
#print(related_recipes)
return {'related': related_recipes}
else:
return {}
编辑2：
按原样取得我的结果，按顺序排列它们的顺序：
sqs = SearchQuerySet().order_by('-favourite_count')
是这样的：
15
251
10
21
0
15
14
0
0
0
5
8
...
将其更改为sqs = SearchQuerySet().order_by('favourite_count')时会返回：
0
0
25
7
0
0
0
0
0
0
2
0
7
0
....
同样，我正在排序的字段是IntegerField。除非我遗漏了某些东西，否则按简单数字排序不应该这么困难。