Question

我正在融化，我对SQL的体验在某种程度上是有限的，出于这些目的。假设我有以下两个表：

CUSTOMER_LIST：

id    |    email
-----------------------------------
1     |    mail1@mail.com
2     |    mail2@mail.com
3     |    mail3@mail.com

payment_log

customer_id    |    payment_date    |    payment_type_id
-------------------------------------------------------------
1              |    2016-01-01      |    3
1              |    2016-01-05      |    3
1              |    2016-01-02      |    2
1              |    2016-04-01      |    1
1              |    2016-04-12      |    2
2              |    2016-01-13      |    1
2              |    2016-01-19      |    1
2              |    2016-01-07      |    1
2              |    2016-01-04      |    1
3              |    2016-04-15      |    2

我希望选择的客户必须符合以下条件：

必须在2016-03-22之前付款，任何付款方式，不包括payment_type_id = 3.
必须在2016-03-22之后至少使用payment_type_id = 3进行一次付款。

作为查询结果我需要的客户是customer_id = 1.

Answer 1

我认为你应该在同一个表上使用内连接

SELECT distinct a.customer_id FROM payment_log  as a
INNER JOIN payment_log as b 
        on (a.customer_id = b.customer_id and a.payment_date = b.payment_date)
WHERE (a.payment_date < '2016-03-22' AND a.payment_type_id!=3)
AND  (b.payment_date>2016-03-22 AND b.payment_type_id=3)";

Answer 2

试试这个。

SELECT customer_id 
FROM payment_log 
WHERE payment_date =< '2016-03-22' AND payment_type_id != '3');

Answer 3

尝试类似：

SELECT 
  DISTINCT customer_id 
FROM 
  payment_log 
WHERE 
    (payment_date < '2016-03-22' AND payment_type_id != 3) 
  AND 
    customer_id IN (SELECT DISTINCT customer_id FROM payment_log WHERE payment_date > 2016-03-22 AND payment_type_id = 3);

您可能需要按一下sql语法，但它应该能满足您的需求。

mySQL SELECT介于日期和条件之间

4 个答案: