Question

我有以下代码，我试图从中获取jSON内容;

$url = "http://useragentapi.com/api/v3/json/APIKEY/$ua";
$json = file_get_contents($url);
$json_data = json_decode($json, true);
echo "My Platform: ". $json_data["data.platform_name"];

我需要进入数据然后到platform_name我需要访问JSON object的所有元素，但我可以让代码工作。

JSON结果[$json_data]就是这样。

{
"data": {
        "platform_name": "Mac OSX El Capitan",
        "platform_version": "Mac OS X 10_11",
        "platform_type": "Desktop",
        "browser_name": "Chrome",
        "browser_version": "52.0.2718.0",
        "engine_name": "WebKit",
        "engine_version": "537.36"
        }
}

Answer 1

试试这个：

$json = '{
"data": {
        "platform_name": "Mac OSX El Capitan",
        "platform_version": "Mac OS X 10_11",
        "platform_type": "Desktop",
        "browser_name": "Chrome",
        "browser_version": "52.0.2718.0",
        "engine_name": "WebKit",
        "engine_version": "537.36"
        }
}';

使用json_decode函数解码json，并将第二个参数用作true，以便将关联数组作为输出。

$arr = json_decode($json, true);

<强>结果

Array
(
    [data] => Array
        (
            [platform_name] => Mac OSX El Capitan
            [platform_version] => Mac OS X 10_11
            [platform_type] => Desktop
            [browser_name] => Chrome
            [browser_version] => 52.0.2718.0
            [engine_name] => WebKit
            [engine_version] => 537.36
        )

)

echo $arr['data']['platform_name'];

<强>输出：

Mac OSX El Capitan

如果你不使用true作为json_decode的第二个参数，那么你必须这样做这样：

$arr = json_decode($json);

echo $arr->data->platform_name; //Mac OSX El Capitan

Answer 2

试试这个

$json = '{
    "data": {
    "platform_name": "Mac OSX El Capitan",
    "platform_version": "Mac OS X 10_11",
    "platform_type": "Desktop",
    "browser_name": "Chrome",
    "browser_version": "52.0.2718.0",
    "engine_name": "WebKit",
    "engine_version": "537.36"
    }
}';


$arr = json_decode($json);
echo $arr->data->platform_name;

使用json_decode函数在PHP中解析JSON对象

2 个答案: