Question

我想创建一个app.if数据连接，然后自动显示toast。否则不显示。我创建了很多应用程序，但我不知道如何做到这一点。我试试这个但不行。

公共类MainActivity扩展了Activity {

private WebView webView;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);


    setContentView(R.layout.main);
    webView = (WebView) findViewById(R.id.wv);
    if(CheckNetwork.isInternetAvailable(MainActivity.this))
    {
        CookieManager cookieManager = CookieManager.getInstance(); 
        cookieManager.setAcceptCookie(true); 

        // webView = (WebView) findViewById(R.id.wv);
        // webView.setWebViewClient(new MyWebViewClient());
        webView.getSettings().setJavaScriptEnabled(true);
        webView.setWebChromeClient(new WebChromeClient() {
                public void onProgressChanged(WebView view, int progress) {
                    // Activities and WebViews measure progress with different scales.
                    // The progress meter will automatically disappear when we reach 100%
                    MainActivity.this.setProgress(progress * 1000);
                }
            });
        webView.setWebViewClient(new WebViewClient() {
                public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) {
                    Toast.makeText(MainActivity.this, "Oh no! " + description, Toast.LENGTH_SHORT).show();
                }
            });

        webView.loadUrl("http://slashdot.org/");
    }
    else{
        //no connection
        Toast toast = Toast.makeText(MainActivity.this, "No Internet Connection", Toast.LENGTH_LONG);
        toast.show();  
    }


}   



@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
    if ((keyCode == KeyEvent.KEYCODE_BACK) && webView.canGoBack()) {
        webView.goBack();
        return true;
    }
    else
    {
        finish();
    }
    return super.onKeyDown(keyCode, event);
}

}

Answer 1

以下是可以通过互联网访问的代码：

 //===================== INTERNET CHECK===========
        public boolean isConnectingToInternet(Context context) {
            boolean connected = false;
            ConnectivityManager CManager = (ConnectivityManager) context
                    .getSystemService(Context.CONNECTIVITY_SERVICE);
            NetworkInfo NInfo = CManager.getActiveNetworkInfo();
            if (NInfo != null && NInfo.isConnectedOrConnecting()) {
                try {
                    if (InetAddress.getByName("www.rameshkhatri.com").isReachable(7000)) { // you change to your website name
                        // host reachable
                        connected = true;
                    } else {
                        connected = true;
    //                    connected = false;
                        // host not reachable
                    }
                } catch (UnknownHostException e) {
                    e.printStackTrace();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return connected;
        }

但是你在AsyncTask中检查了互联网连接，因为网络调用不会在UIThread上，否则你会得到异常。希望这可以帮助。随时询问您是否有疑问

当网络连接打开时自动显示吐司

1 个答案: