我的目的是在我的网站上放一个包含来自数据库中包含ID的字段的表
$con = mysqli_connect('hostname','username','password','dbname');
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
$sql="SELECT * FROM Orders WHERE `Student UID` = '".$id."'";
$result = mysqli_query($con,$sql);
echo
echo "<table><tr><th>Product</th><th>Cost</th></tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['MenuItemName'] . "</td>";
echo "<td>" . $row['Price'] . "</td>";
echo "</tr>";
}
echo "</table>";
在我运行这个时,我正突然得到一张像这样的桌子
+---------+-------+
| Product | Price |
+---------+-------+
我的数据库看起来像这样
+--------------+-------+-------------+
| MenuItemName | Price | Student UID |
+--------------+-------+-------------+
| Foo | 99 | 12345 |
| Foo2 | 11 | 11111 |
| Foo2 | 11 | 12345 |
+--------------+-------+-------------+
我做错了什么?
答案 0 :(得分:0)
尝试更改此行:
$sql="SELECT * FROM Orders WHERE 'Student UID' = '".$id."'";
为:
$sql="SELECT * FROM Orders WHERE `Student UID` = '".$id."'";
喊出来解决你的问题。