将UIPickerView选择存储到变量中

Question

如何将UIPickerView选择存储到变量中？

func pickerView(pickerView: AKPickerView, didSelectItem item: Int) {
}

let selected = pickerView(samplePickerView, what goes here?)  

Answer 1

首先，我猜你会拿着一个数组。因此，让我们将其命名为pickerarray，并将其作为字符串数组。

func pickerView(pickerView: UIPickerView!, didSelectRow row: Int, inComponent component: Int){
   selected = pickerarray[row] // selected is the variable
}

这里使用的是pickerview的row属性。

修改  为了您的澄清，我输入了整个代码

import UIKit


class ViewController: UIViewController,  UIPickerViewDataSource,UIPickerViewDelegate {

@IBOutlet var MyPickerView: UIPickerView!
var selected = ""
let words: NSArray = ["Cat", "Chicken", "fish", "Dog",
    "Mouse", "Guinea Pig", "monkey"]

override func viewDidLoad() {
    super.viewDidLoad()
    MyPickerView.delegate = self
    MyPickerView.dataSource = self

    selected = words[0] // setting the default value

}
func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
    return words.count
}
func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
    return "\(words[row])"
}
func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
    selected = words[row] as! String
}
func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int {
    return 1
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
 }
}

要从任何函数的pickerview访问所选值，请使用

let selectedvalue = selected