Question

我的表

Name  column1 column2 column3
Julio 24      25      35
Jaime 30      40      35

这是我的查询

Select a.name, max(column1+column2+column3) from table group by name

如何获得多列总和的最大值？

Answer 1

使用您的查询

select name, column1+column2+column3 as sum
from table t
join (select max(column1+column2+column3) as maxsum from table) t1
on t.column1+column2+column3 = t1.maxsum

结果将是所有名称及其列的总和，并假设每个名称将具有一个对应的行。

如果您需要与总和的最大值相对应的名称，请使用

select max(column1+column2+column3) as maxsum from table

要获得最大金额使用

Weather = LOAD 'hdfs:/home/hduser/final/Weather.csv' USING PigStorage(',');
A = FOREACH Weather GENERATE (int)$0 AS year, (int)$1 AS month, (int)$2 AS day, (int)$4 AS temp, $14 AS cond, (double)$5 as dewpoint , (double)$10 as wind;


group_by_day = GROUP A BY (year,month,day);

Answer 2

我会使用order by和fetch first 1 row only（在Oracle 12 +中）处理此问题：

Select a.name,
       sum(coalesce(column1, 0) + coalesce(column2, 0) + coalesce(column3, 0)) as s
from table
group by a.name
order by sum(coalesce(column1, 0) + coalesce(column2, 0) + coalesce(column3, 0))  desc
fetch first 1 row only;

在早期版本中，使用子查询：

select t.*
from (Select a.name,
             sum(coalesce(column1, 0) + coalesce(column2, 0) + coalesce(column3, 0)) as s
      from table
      group by a.name
      order by sum(coalesce(column1, 0) + coalesce(column2, 0) + coalesce(column3, 0))  desc
     ) t
where rownum = 1;

Answer 3

我在SQL Server 2014中执行了此查询。希望这会对你有所帮助

select name, max(column1+column2+column3) as MaxSum from table
group by name
having max(column1+column2+column3)= (select max(column1+column2+column3) from table)

如何在SQL中获取多列总和的最大值？

3 个答案: