我需要一些帮助。我的问题是我试图在Django 1.9中加入多个表/模型((问题,答案,用户))以获得有多少答案具有某个用户提出的一组问题
我已经有了我想要的SQL查询:
SELECT q.id, q.title, COUNT(a.id) AS total_answers
FROM review_question AS q
JOIN review_answer AS a ON q.id = a.question_id
JOIN users_user AS u ON q.user_id = u.id
WHERE q.user_id = 1
GROUP BY q.id, q.title;
这是我的模特:
review / models.py
[问题]
class Question(models.Model):
user = models.ForeignKey(User, db_index=True, null=True, blank=True)
tag = models.ManyToManyField(Tag)
title = models.CharField(max_length=200)
[答案]
class Answer(models.Model):
question = models.ForeignKey(Question)
user = models.ForeignKey(User, db_index=True, null=True, blank=True)
users / models.py
[用户]
class User(models.Model):
username = models.CharField(max_length=100, unique=True)
顺便说一下,在我的文件 users / views.py 中我有下一个:
class UserDetailView(DetailView):
model = User
def get_context_data(self, **kwargs):
# calling the get_context_data parent here
questions = Question.objects.filter(user = context['object']).order_by('created')
但是,我只是得到了用户所做的所有问题。
我已经尝试了一段时间寻找如何将上述查询翻译成django-orm但是,我仍然无法做到这一点。任何帮助都会很感激。
答案 0 :(得分:0)
最后我可以帮助解决问题。
我做的是下一个:
在我的文件 users / views.py
中class UserDetailView(DetailView):
model = User
def get_context_data(self, **kwargs):
# Calling the get_context_data parent
questions = Question.objects.filter(user = context['object']).order_by('created')
tags = [ question.tag.all() for question in questions ]
total_answers = self.get_total(questions) # Calling the function that return the total answer by question of a specific user
context['question_tags'] = zip(questions, tags, total_answers) #Zipping the lists with results to use it in the template
return context
def get_total(self, questions):
#Return the total answers that a question has (Here is the trick!)
return [
Answer.objects.filter(question__id=question.id).annotate(num_answers=Count('question')).count() for question in questions]
我是他所做的一切。
最后,我要特别感谢@PauloAlmeida和@MikeVelazco的帮助!