Question

我试图只计算路径中的目录，但它不起作用。所以，我不想为文件和目录编号，我只想要目录。请问你能帮帮我吗？代码：

int listdir(char *dir) {
    struct dirent *dp;
    struct stat s;
    DIR *fd;
    int count = 0;

    if ((fd = opendir(dir)) == NULL) {
        fprintf(stderr, "listdir: can't open %s\n", dir);
    }
    while ((dp = readdir(fd)) != NULL) {
        if (!strcmp(dp->d_name, ".") || !strcmp(dp->d_name, ".."))
            continue;
        stat(dp->d_name, &s);
        if (S_ISDIR(s.st_mode))
        count++;
    }
    closedir(fd);
    return count;
}

Answer 1

你的stat（）调用将失败，因为你不在正确的目录中。您可以通过更改当前目录或生成完整路径并将stat作为参数来解决。

有些Unix，你可以通过查看struct dirent，d_type字段来优化stat调用

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Answer 2

我想你想......

用C写的
计算路径中的目录数。
计数功能将返回#include <stdio.h> #include <glob.h> #include <string.h> #define MAX_PATH 1023 int countDirectories(char* dir) { char path[MAX_PATH] = ""; strcat(path, dir); strcat(path, "/*"); glob_t globbuf; long i, count = 0; if (glob(path, GLOB_NOSORT | GLOB_ONLYDIR, NULL, &globbuf) == 0) { count = globbuf.gl_pathc; for (i = 0; i < globbuf.gl_pathc; i++) { count += countDirectories(globbuf.gl_pathv[i]); } } globfree(&globbuf); return count; } int main(int argc, char* argv[]) { int count; if (argc > 1) { count = countDirectories(argv[1]); } else { count = countDirectories("."); } printf("there are %d directories.\n", count); return 0; }值。

我不了解您的环境，所以它只是一个示例解决方案。

如果您可以使用glob，则可以轻松计算目录数。那就是：main.c

> gcc main.c -o testglob
> ./testglob /path/to/target/dir

您可以尝试这样：

path = /path/to/target/dir/*, there are N directories

然后你会收到这样的输出：

public class items
{
    public string infoOne { get; set;}
    public string infoTwo { get; set;}
    public string infoFull
    {
        get { return $"{infoOne} {infoTwo}"; }
    }
}

感谢。

如何仅计算路径中的目录数

2 个答案: