Question

我正在尝试设置swagger来测试具有IFormFile属性的模型。例如，我有下一个api方法

[HttpPost]
public ApiResult<UserModel> SaveTestFileData([FromForm]TestPostFileArgs args)
{
    var result = new UserModel() { Id = 1, Name = $"SaveTestFileData {args.UserId} company: {args.CompanyId}, file length: {args.CompanyFile.Length}" };
    return ApiResult.Success(result);
}

我的参数模型

public class TestPostFileArgs
{
    public int UserId { get; set; }
    public int? CompanyId { get; set; }
    public IFormFile CompanyFile { get; set; }
}

默认情况下，swagger会生成帮助页面，该页面不允许对其进行测试为了解决这个问题，我写了下一个OperationFilter

public class FormFileOperationFilter: IOperationFilter
{
    public void Apply(Operation operation, OperationFilterContext context)
    {
        if (operation.Parameters == null)
            return;

        var fileParamNames = context.ApiDescription.ActionDescriptor.Parameters
            .SelectMany(x => x.ParameterType.GetProperties())
            .Where(x => x.PropertyType.IsAssignableFrom(typeof (IFormFile)))
            .Select(x => x.Name)
            .ToList();
        if (!fileParamNames.Any())
            return;

        var paramsToRemove = new List<IParameter>();
        foreach (var param in operation.Parameters)
        {
            paramsToRemove.AddRange(from fileParamName in fileParamNames where param.Name.StartsWith(fileParamName + ".") select param);
        }
        paramsToRemove.ForEach(x => operation.Parameters.Remove(x));
        foreach (var paramName in fileParamNames)
        {
            var fileParam = new NonBodyParameter
                {
                    Type = "file",
                    Name = paramName,
                    In = "formData"
                };
            operation.Parameters.Add(fileParam);
        }
        foreach (IParameter param in operation.Parameters)
        {
            param.In = "formData";
        }

        operation.Consumes = new List<string>() { "multipart/form-data" };
    }
}

在这种情况发生之后，正如我所期待的那样昂首阔步。

目前这个解决方案对我有用，但感觉不对。也许我错过了一些简单的解决方案。此方法也不使用IFormFile处理List或复杂对象属性，也可能不处理其他内容。

Answer 1

对于ASP.NET Core开发人员，Swashbuckle.AspNetCore GitHub存储库中存在一个问题：https://github.com/domaindrivendev/Swashbuckle.AspNetCore/issues/193。它在评论中也有一些适用于OperationFilter的工作代码 - 对于我来说，这个代码比这个问题中的其他代码更好。

Answer 2

我有同样的问题，你的解决方案帮助了我。

我刚刚更改了OperationFilter，因为我的IFormFile参数不是嵌套参数，而是action方法的主要参数。

public class AddFileUploadParams : IOperationFilter
{
    public void Apply(Operation operation, OperationFilterContext context)
    {
        if (operation.Parameters == null)
            return;

        var formFileParams = context.ApiDescription.ActionDescriptor.Parameters
                                .Where(x => x.ParameterType.IsAssignableFrom(typeof(IFormFile)))
                                .Select(x => x.Name)
                                .ToList(); ;

        var formFileSubParams = context.ApiDescription.ActionDescriptor.Parameters
            .SelectMany(x => x.ParameterType.GetProperties())
            .Where(x => x.PropertyType.IsAssignableFrom(typeof(IFormFile)))
            .Select(x => x.Name)
            .ToList();

        var allFileParamNames = formFileParams.Union(formFileSubParams);

        if (!allFileParamNames.Any())
            return;

        var paramsToRemove = new List<IParameter>();
        foreach (var param in operation.Parameters)
        {
            paramsToRemove.AddRange(from fileParamName in allFileParamNames where param.Name.StartsWith(fileParamName + ".") select param);
        }
        paramsToRemove.ForEach(x => operation.Parameters.Remove(x));
        foreach (var paramName in allFileParamNames)
        {
            var fileParam = new NonBodyParameter
            {
                Type = "file",
                Name = paramName,
                In = "formData"
            };
            operation.Parameters.Add(fileParam);
        }
        foreach (IParameter param in operation.Parameters)
        {
            param.In = "formData";
        }

        operation.Consumes = new List<string>() { "multipart/form-data" };
    }
}

我想你使用SwashBuckle来生成招摇。如果swashBuckle会处理这个问题会很好。如果我还有时间，也许我会做出贡献。

Answer 3

使用

   [Route("picture/pics/upload/")]

途中

和

UploadPicture(IFormFile file)

在方法中完整的代码是

    [Route("picture/{Id:int:min(1)}/{sequence:int:min(1)}")]
    [SwaggerResponse((int)HttpStatusCode.NotFound)]
    [SwaggerResponse((int)HttpStatusCode.BadRequest)]
    [SwaggerResponse((int)HttpStatusCode.InternalServerError)]
    [SwaggerResponse((int)HttpStatusCode.OK, "The picture uploaded")]
    [SwaggerOperation(
        Summary = "upload a picture for new picture",
        Description = "This action upload a picture for new picture",
        OperationId = "UploadPictureAsync",
        Tags = new[] { "Pictures:Post" }
    )]
    public async Task<ActionResult> UploadPictureAsync(int storeId, byte 
    sequence, IFormFile file )
    {
       ...
    }

用于IFormFile的Asp.Net Core swagger帮助页面

3 个答案: