创建了一个sql搜索查询,我创建了多个字段,如果使用if else条件它工作正常但是如果1和第2个字段是emty而第3个字段不是那么它因为OR关键字而不能正常工作请告诉我怎么做能纠正这个
<form method="POST" action="search.php?action=go">
<li>
<h3>Player</h3>
<input type="text" class="form-control" placeholder="Dylan Scout" name="playername" value="<?php if(isset($_POST["playername"])) {echo $_POST["playername"];} ?>">
</li>
<li>
<h3>Age</h3>
<input type="text" class="form-control" placeholder="25" name="age" value="<?php if(isset($_POST["age"])) {echo $_POST["age"];} ?>">
</li>
<li>
<h3>Country</h3>
<input type="text" class="form-control" placeholder="Wallabies" name="country" value="<?php if(isset($_POST["country"])) {echo $_POST["country"];} ?>">
</li>
<li>
<h3>Club</h3>
<input type="text" class="form-control" placeholder="Eagle" name="club" value="<?php if(isset($_POST["club"])) {echo $_POST["club"];} ?>">
</li>
<li>
<button type="submit" name="search">Search</button>
</li>
</form>
这是我的sql php查询
<?php
if(isset($_GET["action"]) == 'go') {
$stmt = "SELECT * FROM users WHERE";
if($_POST["playername"]) {
$stmt .= " OR fname LIKE '%".$_POST["playername"]."%' OR lname LIKE '%".$_POST["playername"]."%'";
}
if($_POST["age"]) {
$stmt .= " OR age LIKE '%".$_POST["age"]."%' ";
}
if($_POST["country"]) {
$stmt .= " OR country LIKE '%".$_POST["country"]."%' ";
}
if($_POST["club"]) {
$stmt .= " OR club LIKE '%".$_POST["club"]."%' ";
}
} else {
$stmt = "SELECT * FROM users ";
}
echo $stmt . "<br />";
$sql = mysqli_query($connection, $stmt);
?>
请告诉我如何才能使其正常工作,就好像我在第3个字段上写字并将其他字段留空,然后它将变为asWHERE OR,这将成为明显错误的查询并且无法正常工作
谢谢
答案 0 :(得分:4)
函数implode可以帮助您。
将它们添加到数组中并在之后连接它们。
<?php
$array = array();
if (isset($_POST["playername"]))
$array[] = "fname LIKE '%".$_POST["playername"]."%' OR lname LIKE '%".$_POST["playername"]."%";
if (isset($_POST["age"]))
...
$stmt = "SELECT * FROM users";
if (count($array) > 0)
$stmt .= " WHERE " . implode(" OR ",$array);
$sql = mysqli_query($connection, $stmt);
?>
答案 1 :(得分:0)
试试这个。使用implode()
即可实现此目标。
<?php
if(isset($_GET["action"]) == 'go') {
$where = array();
if($_POST["playername"]) {
$where[] = " OR fname LIKE '%".$_POST["playername"]."%' OR lname LIKE '%".$_POST["playername"]."%'";
}
if($_POST["age"]) {
$where[] = " OR age LIKE '%".$_POST["age"]."%' ";
}
if($_POST["country"]) {
$where[] = " OR country LIKE '%".$_POST["country"]."%' ";
}
if($_POST["club"]) {
$where[] = " OR club LIKE '%".$_POST["club"]."%' ";
}
if(!empty($where))
{
$stmt = "SELECT * FROM users WHERE " . implode(" AND ", $where) ." ";
}
else
{
$stmt = "SELECT * FROM users ";
}
} else {
$stmt = "SELECT * FROM users ";
}
echo $stmt . "<br />";
$sql = mysqli_query($connection, $stmt);
?>
答案 2 :(得分:0)
将where条件添加到数组中,然后使用implode function,例如:
<?php
if(isset($_GET["action"]) == 'go') {
$stmt = "SELECT * FROM users";
if($_POST["playername"]) {
$where[] = "fname LIKE '%".$_POST["playername"]."%' OR lname LIKE '%".$_POST["playername"]."%'";
}
if($_POST["age"]) {
$where[] = "age LIKE '%".$_POST["age"]."%' ";
}
if($_POST["country"]) {
$where[] = "country LIKE '%".$_POST["country"]."%' ";
}
if($_POST["club"]) {
$where[] = "club LIKE '%".$_POST["club"]."%' ";
}
if(count($where))
$stmt .= " WHERE " . implode(" OR ", $where);
echo $stmt . "<br />";
$sql = mysqli_query($connection, $stmt);
?>