Question

我正在尝试从swift（2.2）中的json文件中读取电子邮件，这是：

 { "employees" : [
  {
    "name": "sudhanshu",
    "email": "sudhanshu.bharti@digitalavenues.com",
    "password": "password"
    "profilePic": ""
 },
 {
    "name": "prokriti",
    "email": "prokriti.roy@digitalavenues.com",
    "password": "password@123",
    "profilePic": ""
  }
]}

但我收到错误＆＃34;错误域= NSCocoaErrorDomain代码= 3840＆＃34;字符128周围未转义的控制字符。＆＃34; UserInfo = {NSDebugDescription =字符128周围未转义的控制字符。}＆＃34;我已经看过早些时候的帖子，但无法找到确切的问题在哪里？

if let path = NSBundle.mainBundle().pathForResource("Employees", ofType: "json") {
        if let data = NSData(contentsOfFile: path) {
            do {
                let jsonResult: NSDictionary = try NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers) as! NSDictionary

                if let error = jsonResult["error"] {
                    print("Error is: \(error)")
                } else {
                    if let person = jsonResult["email"] {
                        print(person) // dictionary[@"quotables"]
                    }
                }

            } catch let error as NSError {
             print("Error is: \(error)")
            }

        }
    }

提前致谢！

Answer 1

＆＃34;密码＆＃34;：＆＃34;密码“

应该是

＆＃34;密码＆＃34;：＆＃34;密码＆＃34;

您的”字符无效，而不是"。

<强>更新

现在您已修复了无效字符，您可以访问您的数据。但是，如果我相信你向我们展示的JSON摘录，那你就试图将NSDictionary作为一个实际上是阵列的东西。

所以你应该在do：

中做这样的事情

if let jsonResult = try NSJSONSerialization.JSONObjectWithData(data, options: []) as? [[String: String]] {
    for jsonDictionary in jsonResult {
        if let person = jsonDictionary["email"] {
            print(person)
        }
    }
}

更新并修复

if let jsonResult = try NSJSONSerialization.JSONObjectWithData(data, options: []) as? [String: AnyObject] {
    if let employees = jsonResult["Employees"] as? [[String:String]] {
        for employee in employees {
            if let person = employee["email"] {
                print(person)
            }
        }
    }
}

Answer 2

您正尝试直接从字典中访问电子邮件密钥。而你需要首先从密钥＆＃34;员工＆＃34; ＆安培;那么你需要从＆＃34;电子邮件＆＃34;获得价值。键。

if let path = NSBundle.mainBundle().pathForResource("Employees", ofType: "json") {
if let data = NSData(contentsOfFile: path) {
    do {
        let jsonResult: NSDictionary = try NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers) as! NSDictionary

        if let error = jsonResult["error"] {
            print("Error is: \(error)")
        } else {
            let person = jsonResult["employees"] as! NSArray
            for i in 0..<person.count
            {
                let dict = person.objectAtIndex(i) as! NSDictionary
                let strEmail = dict["email"] as! String
                print(strEmail)
            }
        }

    } catch let error as NSError {
        print("Error is: \(error)")
    }

}

如何从swift2中的json读取数据

2 个答案: