Question

我有以下json

 {"status":1,"value":{"details":{"40404000024769":[{"name":"","email":""}]}}}

我解析它如下，

NSString *statusCode = [NSString stringWithFormat:@"%@",jsonDic[@"status"]];
             NSDictionary *valueDict = [jsonDic objectForKey:@"value"];
             NSArray *details = [valueDict objectForKey:@"details"];

             NSLog(@"%@",details);
             for (NSDictionary *response in details){
                 NSLog(@"adsf %@",response);
             }
         }

以下是我的错误日志

这可以获得唯一的40404000024769，但不能获得40404000024769的值。我尝试使用[response valueForKey:@"name"]并且应用崩溃了。我怎样才能获得姓名，电子邮件的价值？

2016-04-27 16:24:02.967 Vaighai Export[311:10625] ***Terminating app due to uncaught exception 'NSUnknownKeyException', reason:'[<__NSCFString 0x14e56870> valueForUndefinedKey:]:this class is not key value coding-compliant for the key name.'

Answer 1

您的JSON结构是：

-NSDictionary
--Number
--NSDictionary
---NSDictionary
----NSDictionary
-----NSArray
------NSDictionary

键details有一个字典作为值，而不是你假设的数组。将您的代码更改为：

注意：这只是向您展示如何解析错误的示例。您需要在应用程序中处理真实世界json的案例。

NSString *statusCode = [NSString stringWithFormat:@"%i",jsonDic[@"status"]]; //We got status
NSDictionary *valueDict = [jsonDic objectForKey:@"value"]; //We got value dic
NSDictionary *detailDic = [valueDict objectForKey:@"details"]; //We got details dic

NSArray * internalArr = [detailDic objectForKey:@"40404000024769"]; //We got array of dictionaries
 //Iterate over this array to log internal dictionaries
for(NSDictionary *nameDic in internalArr)
{
    NSLog(@"Name: %@ email: %@",[nameDic objectForKey:@"name"],[nameDic objectForKey:@"email"]);
}

Answer 2

首先从详细信息字典中获取allkeys，然后将这些键放入数组中，然后在该数组的零索引处，该键可用，找到该键内的数组。

Answer 3

使用此代码

 NSDictionary *valueDict = [jsonDic objectForKey:@"value"];

    NSDictionary *details = [valueDict objectForKey:@"details"];

    NSArray *YourArray= [details  objectForKey:@"40404000024769"];

    NSString *Name = [YourArray objectAtIndex:0]valueForKey:@"name"];
    NSString *Email = [YourArray objectAtIndex:0]valueForKey:@"email"];

Answer 4

status是一个整数

NSInteger statusCode = [jsonDic[@"status"] integerValue];

value包含字典details

NSDictionary *valueDict = [jsonDic objectForKey:@"value"];
NSDictionary *details = [valueDict objectForKey:@"details"];

details包含字典中的数组。在数组的第0项中，有一个包含所请求的name和email键的字典。

for (NSString *key in details){
   NSLog(@"key %@",key);
   NSDictionary *data = details[key][0];
   NSLog(@"name %@ - email %@", data[@"name"], data[@"email"]);
}

Answer 5

key 40404000024769是一个不是数组的字典。

只需添加一行即可获取NSDictionary *valueDict = [jsonDic objectForKey:@"value"]; NSDictionary *details = [valueDict objectForKey:@"details"]; NSArray *ar = [details objectForKey:@"40404000024769"]; for (NSDictionary *response in ar){ NSLog(@"name: %@ email: %@",[response objectForKey:@"name"],[response objectForKey:@"email"]); }键值。

将代码更改为：

date

试图解析一个json崩溃的应用程序

5 个答案: