Question

我有一个网页，旨在允许用户上传文件并提交评论。然后应将文件和相应的注释输入MySQL数据库。目前，如果有人试图这样做，则上传文件并将链接插入到数据库中。但是，注释永远不会进入数据库。该网页包含以下代码：

$('.edit').click(function (e) {
    $(e.target).prev().toggle();
});

文件uploadform.php由

给出

<div style="padding-left: 225px; padding-top: 15px; padding-bottom: 15px; background-color: #754f00; border-style: solid; border-weight: 4px; border-color: black;">

<div class="uploadbox"  style='margin-left: 100px'>

<? include('uploadform.php') ?>
<? include('uploader.php'); ?>


</div>

<center>
<? include('testpost.php'); ?>
</center>

</div>


<br>
<hr>
<br>


<center>

<? include('feed.php'); ?>

</center>

文件uploader.php包含以下内容：

<form enctype="multipart/form-data" method="POST">

    Comment:<br />
    <textarea name='comment' id='comment'></textarea><br />

    <input type="hidden" name="MAX_FILE_SIZE" value="10000000" />

    Choose a file to upload: <input name="uploadedfile" type="file" /><br />

    <input type="submit" value="Submit" />


</form>

文件testpost.php包含

<?php

if( $_POST ){
// Where the file is going to be placed 
$target_path = "uploads/";

/* Add the original filename to our target path.  
Result is "uploads/filename.extension" */
$target_path = $target_path .time() .basename( $_FILES['uploadedfile']['name']);

if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
    echo "The  <a href=" . $target_path . ">file</a> has been uploaded! <br /> LINK: " . $target_path;

  $con = mysql_connect("localhost","theshitp_user","password");

  if (!$con)
  {
    die('Could not connect: ' . mysql_error());
  }

  mysql_select_db("theshitp_posts", $con);

  $query = "
  INSERT INTO `theshitp_posts`.`test2` (`file`) VALUES ( '$target_path' );";

  mysql_query($query);

  echo "<p style='color: grey;'><b>Thank you for your Comment!</b></p>";

  mysql_close($con);


} else{
    echo "There was an error uploading the file, please try again!";
}

}

?>

任何人都可以看到为什么文件链接正在输入数据库，但是评论不是吗？ id和timestamp字段也正确输入到数据库中。

Answer 1

查看testpost.php文件中的查询参数 - ＆gt;

$query = "
  INSERT INTO `theshitp_posts`.`test2` (`id`, `comment`, `timestamp`) VALUES (NULL, '$users_comment', CURRENT_TIMESTAMP() );";

查询参数中的第一个分号是删除这个内部＆＃39 ;;＆＃39; first $ query =＆＃34;;＆＃34 ;; ＆lt; - 在查询和

中

第二id = NULL＆lt; - 在主键的情况下不允许，自动增量可以为空但不是NULL

所以新查询

$query = " INSERT INTO `theshitp_posts`.`test2` (`id`, `comment`, `timestamp`) VALUES ('', '$users_comment', CURRENT_TIMESTAMP() )";

Answer 2

您正试图将Null插入＆＃39; id＆＃39;必须是主键，因此此查询无效，您需要更正它。见 - SQL Server, can't insert null into primary key field?

为什么评论没有上传到MySQL数据库？

2 个答案: