Question

我使用Oracle“pivot XML”生成以下格式化的XML，即：

<?xml version="1.0" encoding="UTF-8"?>
<PivotSet>
   <item>
      <column name="INTERFACE_NO">1</column>
      <column name="INTERFACE_NAME_A">abc1</column>
      <column name="INTERFACE_L">11</column>
      <column name="INTERFACE_R">22</column>
   </item>
   <item>
      <column name="INTERFACE_NO">2</column>
      <column name="INTERFACE_NAME_A">abc2</column>
      <column name="INTERFACE_L">33</column>
      <column name="INTERFACE_R">44</column>
   </item>
   <item>
      <column name="INTERFACE_NO">3</column>
      <column name="INTERFACE_NAME_A">abc3</column>
      <column name="INTERFACE_L">55</column>
      <column name="INTERFACE_R">66</column>
   </item>
   <item>
      <column name="INTERFACE_NO">4</column>
      <column name="INTERFACE_NAME_A">abc4</column>
      <column name="INTERFACE_L">77</column>
      <column name="INTERFACE_R">882</column>
   </item>
</PivotSet>

基于上面的XML，使用Oracle SQL（11g）如何提取上面的所有值？

例如，我一直在使用以下内容，即

select 
        extractvalue(aggregated_interface_no_xml,'/PivotSet/item[2]/column[1]') aa,
        extractvalue(aggregated_interface_no_xml,'/PivotSet/item[2]/column[2]') bb,   
        extractvalue(aggregated_interface_no_xml,'/PivotSet/item[2]/column[3]') cc,
        extractvalue(aggregated_interface_no_xml,'/PivotSet/item[2]/column[4]') dd
from t

但这只会返回与INTERFACE_NO 2相关的数据。

我不确定如何针对/PivotSet/item传递通配符以返回每个项目的XML PivotSet中的所有记录？

Answer 1

不推荐使用Xmlsequence。 Xmltable是一个很好的干净方法。

.factory('Test', ['$resource', function ($resource) {
  return $resource('data.json');
}])

.controller('MyCtrl', ['$scope', 'Test', function($scope, Test) {

Test.get(function (data) {
  $scope.myData = data;
});

$scope.myFunction = function() {
  var min = $scope.myData.min;
  var max = $scope.myData.max;
  var diff = max - min;
  return diff;
}

}])

Answer 2

您可以使用xml表执行此操作。像这样：

SELECT EXTRACTVALUE(VALUE(xml_list), '//column[1]') AS interface_no
      ,EXTRACTVALUE(VALUE(xml_list), '//column[2]') AS interface_name_a
      ,EXTRACTVALUE(VALUE(xml_list), '//column[3]') AS interface_l
      ,EXTRACTVALUE(VALUE(xml_list), '//column[4]') AS interface_r
  FROM TABLE(XMLSEQUENCE(EXTRACT(XMLType('<?xml version="1.0" encoding="UTF-8"?>
<PivotSet>
   <item>
      <column name="INTERFACE_NO">1</column>
      <column name="INTERFACE_NAME_A">abc1</column>
      <column name="INTERFACE_L">11</column>
      <column name="INTERFACE_R">22</column>
   </item>
   <item>
      <column name="INTERFACE_NO">2</column>
      <column name="INTERFACE_NAME_A">abc2</column>
      <column name="INTERFACE_L">33</column>
      <column name="INTERFACE_R">44</column>
   </item>
   <item>
      <column name="INTERFACE_NO">3</column>
      <column name="INTERFACE_NAME_A">abc3</column>
      <column name="INTERFACE_L">55</column>
      <column name="INTERFACE_R">66</column>
   </item>
   <item>
      <column name="INTERFACE_NO">4</column>
      <column name="INTERFACE_NAME_A">abc4</column>
      <column name="INTERFACE_L">77</column>
      <column name="INTERFACE_R">882</column>
   </item>
</PivotSet>'), 'PivotSet/item'))) xml_list;

Oracle 11g ExtractValue返回所有XML数据

2 个答案: