Question

我有这个代码，它以JSON

的形式返回SQL查询

<?php
$con=mysqli_connect("localhost","user","pw","db");
// Check connection
if (mysqli_connect_errno())
{
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$con->set_charset("utf8");
$result = mysqli_query($con,"SELECT * FROM table");

echo "{";

while($row = mysqli_fetch_array($result))
{
  echo '"' . $row['RowId'] . '"' . ":{";
  echo '"Name": "' . $row['Name'] . '",';
  echo '"Surname": "' . $row['Surname'] . '",';
  echo '"MuEmail": "' . $row['MuEmail'] . '@mahidol.ac.th"';
  echo '},';
}
echo "$bs";
echo "}";

mysqli_close($con);
?>

但回音文本的最后结果，如

{
...
"678":{
    "Name": "xxx",
    "Surname": "yyy",
    "MuEmail": "zzz@example.com"}
,}

观察尾随的逗号，这使得JS的JSON.parse（）失败。

无论如何要删除这个逗号？

Answer 1

使用正确的json创建

$("tr[id="+row.id+"]")

试试这个，它会影响你的json并解决你的问题。

Answer 2

您可以使用条件查看它是否是最后一行，如果是，则不输出逗号。

请参阅更新的代码：

<?php
$con=mysqli_connect("localhost","user","pw","db");
// Check connection
if (mysqli_connect_errno())
{
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$con->set_charset("utf8");
$result = mysqli_query($con,"SELECT * FROM table");

$row_count = 0;
$i = 0;
$row_count = mysqli_num_rows($result);

echo "{";

while($row = mysqli_fetch_array($result))
{
  $i++;
  echo '"' . $row['RowId'] . '"' . ":{";
  echo '"Name": "' . $row['Name'] . '",';
  echo '"Surname": "' . $row['Surname'] . '",';
  echo '"MuEmail": "' . $row['MuEmail'] . '@mahidol.ac.th"';
  if($i < $row_count){
      echo '},';
  }else{
      echo '}';
  }
}
echo "$bs";
echo "}";

mysqli_close($con);
?>

Answer 3

最好的方法是创建一个像

这样的对象数组

$json = array();  
while($row = mysqli_fetch_array($result))  
{  
   // create an object  
   $obj = new stdClass();  
   // add values to the object  
   $obj->Name = $row['Name'];  
   $obj->Surname= $row['Surname'];  
   $obj->MuEmail= $row['MuEmail'] . "'@mahidol.ac.th'";      
   // append the object to the array  
   $json["Reords"][] = $obj;  
}  
echo json_encode($json);

按照您的方式，只需使用以下代码替换您的while循环

$currentRow = 1;   
$count = mysqli-num_rows($result);  
while($row = mysqli_fetch_array($result))  
{  
   echo '"' . $row['RowId'] . '"' . ":{";  
   echo '"Name": "' . $row['Name'] . '",';  
   echo '"Surname": "' . $row['Surname'] . '",';  
   echo '"MuEmail": "' . $row['MuEmail'] . '@mahidol.ac.th"';  
   if($currentRow == $count)  
   {  
       echo '}';  
   }  
   else  
   {  
       echo '},';  
   }  
   $currentRow++;  
}

删除回显的PHP中的尾随逗号

3 个答案: