从scalaJS读取的upickle - upickle.Invalid $ Data：String（data：1）

Question

来自ScalaJS。

import upickle.default._
import scala.scalajs.concurrent.JSExecutionContext.Implicits.queue

case class Post(userId: Long, id: Long, title: String, body: String)

@JSExport
def posts() : Future[Seq[Post]] = {
  val txt = """[{
    "userId": 1,
    "id": 1,
    "title": "sunt aut facere repellat provident occaecati excepturi optio reprehenderit",
    "body": "quia et suscipit\nsuscipit recusandae consequuntur expedita et cum\nreprehenderit molestiae ut ut quas totam\nnostrum rerum est autem sunt rem eveniet architecto"
  }]"""

  val p = read[Seq[Post]](txt)

  println(p)

  p

}

pp onFailure {
  case x => println(x)
}

println（x）print： upickle.Invalid $ Data：String（data：1）

如何让它发挥作用？

更新/同步：https://github.com/lihaoyi/upickle-pprint/issues/154

Answer 1

嗯..

  

＆＃34; uPickle将Longs序列化为＆＃34; 1＆＃34;为了避免   Scala.js中大量数据的损坏/截断。如果他们来了   作为JSON号码，你需要输入它们作为Ints或Doubles＆＃34;