Question

我在尝试删除列表中的逗号时遇到了困难。我尝试过使用split（＆＃39;，＆＃39;）但后来意识到你不能因为它的所有数字。任何建议都会很棒！

class UnorderedList:

def __init__(self):
    self.head = None


def add(self, item): #add to the beginning of the list
    new_node = Node(item)
    new_node.set_next(self.head)
    self.head = new_node

def size(self):
    current = self.head
    count = 0
    while current != None:
        count = count + 1
        current = current.get_next()
    return count

def is_empty(self):
    return self.head == None

def search(self,item):
    current = self.head
    while current != None:
        if current.get_data() == item:
            return True
        else:
            current = current.get_next()
    return False

def remove(self, item):
    #Assumes the item is in the linked list
    current = self.head
    previous = None
    found = False
    while not found:
        if current.get_data() == item:
            found = True
        else:
            previous = current
            current = current.get_next()
    if previous == None:
        self.head = current.get_next() #remove the first node
    else:
        previous.set_next(current.get_next())

def __str__(self):
    my_list1 = []
    current = self.head
    while current != None:
        my_list1 += [current.get_data()]
        current = current.get_next()
    return str(my_list1)

def __iter__(self):
    return LinkedListIterator(self.head)

我的回答是[8,7,6,3,5] 但我希望它是[8 7 6 3 5]

Answer 1

你也可以使用：str（my_list1）.replace（'，'，''）

Answer 2

而不是：

str(my_list1)

执行：

"[{0}]".format(" " .join(str(x) for x in my_list1))

Answer 3

[1 2 3]无效。您可以尝试这样的事情：

' '.join(map(str, your_list))  # => '1 2 3'

如何从列表中删除逗号

3 个答案: