为什么正确的id没有插入表中

Question

我希望以下代码在customer_payment表中插入cars id，但它只选择477 id。我不知道为什么。因为它可以在图像波纹管中看到只有product_id 477插入而不是任何其他如果我选择500它仍然插入477.请帮助我这个帮助将不胜感激。谢谢

include 'admin/db.php';

if(isset($_GET['payment_here'])){

    //select product id from cart
    $select_cart = "select * from cart";
    $runcart = mysqli_query($conn, $select_cart);
    $cartwhile=mysqli_fetch_assoc($runcart);

    $carssid = $cartwhile['P_ID'];
    $cusid = $cartwhile['C_ID'];

    //select id from cars
    $scars = "select * from cars where id=$carssid";
    $scarsrun = mysqli_query($conn, $scars);
    $showcars = mysqli_fetch_assoc($scarsrun);
    $carsdealer = $showcars['dealer'];


    //select customer id from customer  table
    //$selectcust = "select * from customer_register where id=$cusid";
    //insert data into customer payment table
    echo $insertpay = "insert into customer_payment 
    (Product_id, customer_id, dealer) 
    values ( $carssid," . $_SESSION['customer_id'] . ", '$carsdealer')";
    $run_inserts = mysqli_query($conn, $insertpay);
    /*
    if($run_inserts){
        echo "<script>window.location.href = 'checkout.php'</script>";
    }
    */
}
?>

Answer 1

你在这里想做什么

$select_cart = "select * from cart";
$runcart = mysqli_query($conn, $select_cart);
$cartwhile=mysqli_fetch_assoc($runcart); // here

从“购物车”中提取第一个条目。表格总是会相同。

你可以尝试这样的事情。

$c_id = $_SESSION['customer_id'];
$select_cart = "select * from cart where C_ID=$c_id";
$runcart = mysqli_query($conn, $select_cart);
$cartwhile=mysqli_fetch_assoc($runcart);

此查询将专门为当前会话的客户提取数据。 您可以按原样使用的其余代码。