Question

下面的图形按钮没有值，只是一个id。我点击它时试图从数据库中获取一些结果。我必须根据图形按钮结构中的 span 获得结果。

<a class="uib-graphic-button default-graphic-sizing default-image-sizing hover-graphic-button active-graphic-button default-graphic-button default-graphic-text widget uib_w_10 d-margins media-button-text-bottom" data-uib="media/graphic_button" data-ver="0" id="admin">
    <img src="images/administrativa.png">
    <span class="uib-caption">Admin</span>
</a>

的javascript：

$(document).on("click", "#admin", function(evt)
{
    /* your code goes here */

    var dataString = "admin=";
    var $server = "http://localhost/project";

    function SelectAdm(){
        $.ajax({
            type: "post",
            url: $server+"/select.php",
            data: dataString,
            success: function(result, jqXHR){

                var vaga = $.parseJSON(result);

                $.each(vaga, function(index, item){
                    var list_item = '<li class="widget uib_w_17" data-uib="jquery_mobile/listitem" data-ver="0" data-icon="carat-r" id="listitem"><a href="#"><span>'+item.CARGO+'</span></a>';

                    $("#list").append(list_item);
                    activate_page("#listpage");

                });

            },
            error: function(jqXHR, status){
                alert("not working");
            }
        });
    }
    new SelectAdm();
});

php文件

<?php 

include_once("conn.php");

if(isset($_POST['admin'])){

$adm = "administrativa";

$sql = $mysqli->query("SELECT * FROM vagas WHERE area = '".$adm."' ");

if($sql->num_rows > 0){
    while($row = $sql->fetch_array(MYSQL_BOTH)){
        $registro = array(
            "AREA" => $row['area'],
            "CARGO" => $row['cargo'],
            "ATIVIDADES" => $row['atividades'],
            "SALARIO_INI" => $row['salario_ini'],
            "POS_EXPERIENCIA" => $row['pos_experiencia'],
            "BENEFICIOS" => $row['beneficios'],
            "HORARIO" => $row['horario'],
            "ESCOLARIDADE" => $row['escolaridade'],
            "LOCAL" => $row['local'],
            "INFOS_ADICIONAIS" => $row['infos_adicionais']                      
        );

        $retorno[] = $registro;

    }       
}

$mysqli->close();
$retorno = json_encode($retorno);
echo $retorno;

}

?>

我发错了吗？当我使用输入时，一切正常，安装数据如下：

var state = $("#state").val(); 
var city =$("#city").val();
var dataString = "state="+state+"&city="+city+"&submit=";

如果没有投入，它如何运作？

Ajax使用图形按钮发送发布数据

0 个答案: