Question

我在一个数据库中有多个MySQL表，每个表记录执行的事务。每个表都有一个DATETIME字段，用于记录每个事务发生的时间。

如何构建MySQL查询或过程来生成每个表的事务计数，按每个日期分组？

我希望看到从当月开始到当天的每天总数。

在每个表中，一行代表一个事务。因此，对于每个日期，列只是每个表中的行数。

运行这样的查询，今天，会产生一个像;

这样的表

26/04/2016 Total A Transactions，Total B Transactions，...

25/04/2016 Total A Transactions，Total B Transactions，...

...

01/04/2016 Total A Transactions，Total B Transactions，...

示例模式;

CREATE TABLE tableA（ uuid BIGINT（20）UNSIGNED NOT NULL AUTO_INCREMENT， creationTime DATETIME NOT NULL，..

CREATE TABLE tableB（ uuid BIGINT（20）UNSIGNED NOT NULL AUTO_INCREMENT， creationTime DATETIME NOT NULL，..

...

Answer 1

select date(my_date), count(*), 'tableA' fromc tableA 
where month(my_date) = month(curdate())
AND year(my_date) = Year(curdate())
group by date(my_date)
union 
select date(my_date), count(*), 'tableB' fromc tableB 
where month(my_date) = month(curdate())
AND year(my_date) = Year(curdate())    
group by date(my_date)

Answer 2

我认为tableA每天至少有一笔交易。

select create_time, total_a_transaction, total_b_transaction, ...
from

(select date(creationTime) create_time, count(*) total_a_transaction
from tableA 
where year(creationTime) = year(curdate()) 
and month(creationTime) = month(curdate())
group by date(creationTime)) transaction_a

left join

(select date(creationTime) create_time, count(*) total_b_transaction
from tableB 
where year(creationTime) = year(curdate()) 
and month(creationTime) = month(curdate())
group by date(creationTime)) transaction_b

using (create_time)

left join ...

MySQL个体从多个表中计数，按日期分组

2 个答案: