Question

我有一个内部联接的嵌套查询，它返回给定＆＃34;软件＆＃34;的多个记录，但我需要在一行中压缩结果... （输出附件）对于一个软件，您会看到多个记录，其中包含已解决的字段＆＃39;并且＆＃39;没有解决＆＃39;，我需要将其压缩到一行，分别显示已解决 - 已解决 - 未解决...例如。但有时候，同一列会有两个或多个＆＃34; Resolved＆＃34;记录。我想创建一个新列，如SPPA2或WCS2等...如果发生这种情况，并将同一列中每条记录的日期合并为＆＃34;已解决＆＃34;或＆＃34;不解决＆＃34; 我是个新手，所以试着理解这个逻辑。

SELECT * FROM
(SELECT act.Vendor  + ' ' + act.[Application Name] + ' ' + act.Version as "Software name"
                ,act.srmNumber as SRM#
                ,ssd.DateAssign

                ,IIF(ssd.DateResolv IS NOT NULL AND ssd.EntryText LIKE '%Step 1%' AND ssd.TargetUnitID = 48, 'Resolved', 'Not Resolved') as SPPA
                ,IIF(ssd.DateResolv IS NOT NULL AND ssd.EntryText LIKE '%Step 2%' AND ssd.TargetUnitID = 39, 'Resolved', 'Not Resolved') as WCS
                ,IIF(ssd.DateResolv IS NOT NULL AND ssd.EntryText LIKE '%Step 3%' AND ssd.TargetUnitID = 738, 'Resolved', 'Not Resolved') as SAM   
FROM [SAMI_Main].dbo.vw_SAM_Software_Deployment AS ssd INNER JOIN [SAMI_Main].dbo.ACT_Inventory AS act ON act.srmNumber = RIGHT(ssd.callID,7)) AS T1
WHERE t1.SPPA = 'Resolved' OR t1.WCS = 'Resolved' OR t1.SAM = 'Resolved'
;

OUTPUT HERE

Answer 1

这是预期的输出吗？

|Software Name|SRM#|SPPA|WCS|SAM|

|SAP...|1456484|Resolved 2015-09-22|Not Resolved|Not Resolved|

|Dessci...|1514703|Resolved 2016-01-20|Not Resolved|Not Resolved|

|Adobe Air...|1525807|Resolved 2016-02-11|Not Resolved|Not Resolved|

如果是这样，此查询可能有效。我无法访问SQL Server，所以我不确定语法：

SELECT DISTINCT software_name AS [Software Name],
SRM#,
IIF(SPPA = 'Resolved', 'Resolved' + ' ' + MAX(DateAssign OVER (PARTITION BY software_name, SPPA), 'Not Resolved') AS SPPA,
IIF(WCS = 'Resolved', 'Resolved' + ' ' + MAX(DateAssign OVER (PARTITION BY software_name, WCS), 'Not Resolved') AS WCS, 
IIF(SAM = 'Resolved', 'Resolved' + ' ' + MAX(DateAssign OVER (PARTITION BY software_name, SAM), 'Not Resolved') AS SAM
FROM
(SELECT act.Vendor  + ' ' + act.[Application Name] + ' ' + act.Version as software_name
,act.srmNumber as SRM#
,ssd.DateAssign
,IIF(ssd.DateResolv IS NOT NULL AND ssd.EntryText LIKE '%Step 1%' AND ssd.TargetUnitID = 48, 'Resolved', 'Not Resolved') as SPPA
,IIF(ssd.DateResolv IS NOT NULL AND ssd.EntryText LIKE '%Step 2%' AND ssd.TargetUnitID = 39, 'Resolved', 'Not Resolved') as WCS
,IIF(ssd.DateResolv IS NOT NULL AND ssd.EntryText LIKE '%Step 3%' AND ssd.TargetUnitID = 738, 'Resolved', 'Not Resolved') as SAM   
FROM [SAMI_Main].dbo.vw_SAM_Software_Deployment AS ssd 
INNER JOIN [SAMI_Main].dbo.ACT_Inventory AS act ON act.srmNumber =     RIGHT(ssd.callID,7)) AS T1
WHERE t1.SPPA = 'Resolved' OR t1.WCS = 'Resolved' OR t1.SAM = 'Resolved';

我在这里使用MAX关键字作为分析函数。我以前是written about the MAX keyword，但是从Oracle的角度来看。我理解它在SQL Server中的工作方式类似。

Answer 2

感谢您的回应，我使用MAX（）为SqlServ清理了代码中的语法。它将输出作为附件...... OUTPUT HERE

所以我只需要将记录压缩到一条记录，每个软件显示每个Resolved列，如果你提供了MAX（）日期，如果每个列中都存在...那么在这个例子中，它将是＆＃34 ; Adobe Air＆＃34;作为一个记录，所有列＆＃34;已解决＆＃34;。另外两个软件是预期的。

SELECT DISTINCT software_name AS [Software Name],

SRM＃， IIF（SPPA =＆＃39;已解决＆＃39;，＆＃39;已解决＆＃39; +＆＃39;（＆＃39; + MAX（DateAssign）OVER（分区来自software_name，SPPA）+＆＃39;）＆＃39;，＆＃39;未解决＆＃39;）作为SPPA， IIF（WCS =＆＃39;已解决＆＃39;，＆＃39;已解决＆＃39; +＆＃39;（＆＃39; + MAX（DateAssign）OVER（按软件名称分配，WCS）+＆＃39;）＆＃39;，＆＃39;未解决＆＃39;）作为WCS， IIF（SAM =＆＃39;已解决＆＃39;，＆＃39;已解决＆＃39; +＆＃39;（＆＃39; + MAX（DateAssign）OVER（PARTITION BY software_name，SAM）+＆＃39;）＆＃39;，＆＃39;未解决＆＃39;）作为SAM 从（SELECT act.Vendor +＆＃39;＆＃39; + act。[Application Name] +＆＃39;＆＃39; + act.Version as software_name ，act.srmNumber as SRM＃，ssd.DateAssign ，IIF（ssd.DateResolv IS NOT NULL和ssd.EntryText LIKE＆＃39;％Step 1％＆＃39; AND ssd.TargetUnitID = 48，＆＃39; Resolved＆＃39;，＆＃39; Not Resolved＆＃39 ;）作为SPPA ，IIF（ssd.DateResolv IS NOT NULL和ssd.EntryText LIKE＆＃39;％Step 2％＆＃39; AND ssd.TargetUnitID = 39，＆＃39; Resolved＆＃39;，＆＃39; Not Resolved＆＃39 ;）作为WCS ，IIF（ssd.DateResolv IS NOT NULL和ssd.EntryText LIKE＆＃39;％Step 3％＆＃39; AND ssd.TargetUnitID = 738，＆＃39; Resolved＆＃39;，＆＃39; Not Resolved＆＃39 ;）作为SAM
FROM [SAMI_Main] .dbo.vw_SAM_Software_Deployment AS ssd INNER JOIN [SAMI_Main] .dbo.ACT_Inventory AS act on act.srmNumber = RIGHT（ssd.callID，7））AS t1 在哪里t1.SPPA =＆＃39;已解决＆＃39;或者t1.WCS =＆＃39;已解决＆＃39;或者t1.SAM =＆＃39;已解决＆＃39;订购SRM＃DESC;

使用表连接在SQL嵌套查询中汇总结果

2 个答案: