Question

我试图让我的Android应用程序截取当前正在运行的活动的屏幕截图，然后将其保存在解析服务器中..但它没有工作...有谁知道什么是＆＃39; s这段代码错了

我的代码......

public class MainActivity extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        Button b = (Button) findViewById(R.id.button);
        b.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {

                takeScreenshot();


            }
        });

    }
    private void takeScreenshot() {
        Date now = new Date();
        android.text.format.DateFormat.format("yyyy-MM-dd_hh:mm:ss", now);

        try {
                           String mPath = Environment.getExternalStorageDirectory().toString() + "/" + now + ".png";

            // create bitmap screen capture
            View v1 = getWindow().getDecorView().getRootView();
            v1.setDrawingCacheEnabled(true);
            Bitmap bitmap = Bitmap.createBitmap(v1.getDrawingCache());
            v1.setDrawingCacheEnabled(false);

            File imageFile = new File(mPath);

            FileOutputStream outputStream = new FileOutputStream(imageFile);
            int quality = 100;
            bitmap.compress(Bitmap.CompressFormat.PNG, quality, outputStream);



            ByteArrayOutputStream stream = new ByteArrayOutputStream();
            Uri uri = Uri.fromFile(imageFile);
            byte[] image = stream.toByteArray();

            // Create the ParseFile
            ParseFile file = new ParseFile(uri.toString(), image);
            // Upload the image into Parse Cloud
            file.saveInBackground();

            // Create a New Class called "ImageUpload" in Parse
            ParseObject imgupload = new ParseObject("Image");

            // Create a column named "ImageName" and set the string

            // Create a column named "ImageFile" and insert the image
            imgupload.put("IMG", file);

            // Create the class and the columns
            imgupload.saveInBackground();

            // Show a simple toast message
            Toast.makeText(MainActivity.this, "Image Uploaded",
                    Toast.LENGTH_SHORT).show();

            outputStream.flush();
            outputStream.close();
        } catch (Throwable e) {
            // Several error may come out with file handling or OOM
            e.printStackTrace();
        }
    }

Answer 1

您应该将代码更改为

bitmap.compress(Bitmap.CompressFormat.PNG, quality, outputStream);
outputStream.flush();// before file usage
outputStream.close();

从方法结束处删除flush。

Answer 2

Parse Work on Thread所以首先回调ParseImage是保存还是不保存，回复响应就像......

    final ParseFile file = new ParseFile(uri.toString(), image);
    // Upload the image into Parse Cloud
    file.saveInBackground(new SaveCallback() {

        @Override
        public void done(ParseException e) {
            // TODO Auto-generated method stub
            if (e == null) {
                // success
               // hear save image
              // upload image into parse
                uploadImgae(file);
            } else {
                // fail
            }
        }
    });

那么这个方法。

public void uploadImgae(ParseFile file) {
    // TODO Auto-generated method stub

    // Create a New Class called "ImageUpload" in
    // Parse
    ParseObject imgupload = new ParseObject("Image");

    // image
    imgupload.put("IMG", file);

    // Create the class and the columns
    imgupload.saveInBackground(new SaveCallback() {

        @Override
        public void done(ParseException e) {
            // TODO Auto-generated method stub
            if (e == null) {
                // success
            } else {
                // fail
            }
        }
    });
}

在解析服务器中保存屏幕截图

2 个答案: