Question

我收到以下错误，但无法找到解决方法

异常类型：TypeError异常值：'EstablishmentType'对象是不可迭代的

类序列化程序：

class TransactionSerializer(serializers.HyperlinkedModelSerializer):
    establishment_from_id = serializers.HyperlinkedRelatedField(view_name='establishment_type', read_only=True, many=True)

class Meta:
    model = Transaction
    fields = ('id', 'created_date', 'updated_date','establishment_from_id', 'quantity', 'owner_id', 'quantity_missing', 'gps_longitude', 'gps_latitude', 'gps_accuracy', 'type')

模型

class Transaction(models.Model):
    created_date = models.DateTimeField()
    updated_date = models.DateTimeField()
    establishment_from_id = models.ForeignKey(EstablishmentType, related_name="establishment_from")
    establishment_to_id = models.ForeignKey(EstablishmentType, related_name="establishment_to")
    quantity = models.FloatField()
    owner_id = models.ForeignKey(User)
    quantity_missing = models.FloatField()
    status = models.ForeignKey(TransactionStatus)
    gps_longitude = models.CharField(max_length=400)
    gps_latitude = models.CharField(max_length=400)
    gps_accuracy = models.CharField(max_length=400)
    type = models.FloatField()

    def __str__(self):
        return str(self.id)

class EstablishmentType(models.Model):
    name = models.CharField(max_length=200)
    #created_by = CreatingUserField(related_name="created_categories")

    def __str__(self):
        return self.name

谢谢！

Answer 1

尝试从Serializer中取出many=True。 establish_from_id是FK而不是M2M，因此对于每个实例，它只有一个值。如果这是EstablishmentType的序列化程序，则有many=True

是有意义的

'EstablishmentType'对象不可迭代

1 个答案: