Question

我有下表：

 ----------------------------
|  id  |  product  |  price  |
 ----------------------------
|  1   |  1        |  50     |
|  2   |  1        |  39     |
|  3   |  1        |  60     |
 ----------------------------

我需要的是获得按产品（1）分组的最低价格（39）并保留最低价格的ID。

我有这个查询

SELECT
    id,
    product,
    MIN(price) AS price
FROM
    variant
GROUP BY
    product

结果

 ----------------------------
|  id  |  product  |  price  |
 ----------------------------
|  1   |  1        |  39     |
 ----------------------------

但我正在寻找的结果是

 ----------------------------
|  id  |  product  |  price  |
 ----------------------------
|  2   |  1        |  39     |
 ----------------------------

有可能实现这个目标吗？

我做了一个小提琴：http://sqlfiddle.com/#!9/d2ddb2

Answer 1

尝试:(不是很优雅但是进一步改变的好平台）

select A.*,B.id from 
(SELECT product,MIN(price) AS minprice 
FROM variant GROUP BY product ) A
inner join 
(SELECT * FROM variant ) B
on A.product = B.product and A.minprice = B.price

Answer 2

您可以将ID除以x（例如1000000，具体取决于ID的限制）并将其添加到价格中。然后取出min并稍后拆分id。这有点偏僻但应该有效。 SELECT product, MIN(price+(id/10000)) AS price FROM variant GROUP BY product

控制组返回的行匹配结果

2 个答案: