Question

我试图用ldapjs执行过滤器取决于第一次搜索结果的搜索

ldapClient.search(base1, opts1, (err1, res1) => {
    res1.on("searchEntry", entry => {
        const myObj = { attr1: entry.object.attr1 }
        const opts2 = { filter: entry.object.filter }

        if (entry.object.condition == myCondition) {
            ldapClient.search(base2, opts2, (err2, res2) => {
                res2.on("searchEntry", entry => {
                    myObj.attr2 = entry.object.attr2
                });
            });
        }

        console.log(myObj);
    });
});

问题是，当console.log最终显示我的对象时，事件＆＃34; .on＆＃34;我的第二次搜索尚未被捕获。

那么，在显示对象之前，如何告诉我的代码等待第二个事件完成？

由于

Answer 1

执行class A: UIViewController { @IBOutlet weak var collectionView: UICollectionView! } class B: A { //Should be empty right? since it inherits from A, // but the collectionView from super class is not initialized. }

时，您无法看到事件结果

由于异步行为，您需要等待第二次搜索完成。

你要把它放在“.on”中：

console.log(myObj)

也适用于优雅代码您可以像以下一样使用它：

ldapClient.search(base1, opts1, (err1, res1) => {
    res1.on("searchEntry", entry => {
        let myObj = { attr1: entry.object.attr1 }
        let opts2 = { filter: entry.object.filter }

        if (entry.object.condition == myCondition) {
            ldapClient.search(base2, opts2, (err2, res2) => {
                res2.on("searchEntry", entry => {
                    myObj.attr2 = entry.object.attr2
                    console.log("res2", myObj);
                });
            });
            return;
        }

        console.log("res1", myObj);
    });
});

Answer 2

谢谢num8er。

我终于使用了＆＃34;承诺的ldap＆＃34;模块，基于ldapjs和promises

ldapClient.bind(dn, password).then(() => {

    let p;

    ldapClient.search(base1, opts1).then(res1 => {
        const entry = res1.entries[0].object;
        const myObj = { attr1: entry.attr1 };

        if (entry.condition == myCondition) {
            const opts2 = { filter: entry.filter }
            p = ldapClient.search(base2, opts2).then(res2 => {
                const entry2 = res2.entries[0].object;
                myObj.attr2 = entry2.attr2;
                return myObj;
            });
        } else {
            p = Promise.resolve(myObj);
        }

        p.then(value => console.log("Obj", value);
    });
});

Ldap.js：嵌套搜索

2 个答案: