我正在使用FuelPHP及其ORM创建REST API,文档位于此处:http://fuelphp.com/docs/packages/orm/crud.html
我可以像这样返回数据库行的对象:
$entry = Model_V1_Inventory::find(1);
这将返回PK等于1的对象,这与预期一致。如何访问_data数组以对其进行json_encode并将其作为REST响应的一部分返回?我只需调用:
即可访问数组中的各个项目$entry->product_ref
作为一个例子,我无论如何都无法看到_data数组被保护。
退回的反对意见:
Model_V1_Inventory Object
(
[_is_new:protected] =>
[_frozen:protected] =>
[_sanitization_enabled:protected] =>
[_data:protected] => Array
(
[product_ref] => from the model
[cost_price] => 0.99
[rrp_price] => 11.67
[current_price] => 5.47
[description] => test description
[created_at] => 2016-04-26 14:29:20
[updated_at] => 2016-04-26 14:29:20
[id] => 1
)
[_custom_data:protected] => Array
(
)
[_original:protected] => Array
(
[product_ref] => from the model
[cost_price] => 0.99
[rrp_price] => 11.67
[current_price] => 5.47
[description] => test description
[created_at] => 2016-04-26 14:29:20
[updated_at] => 2016-04-26 14:29:20
[id] => 1
)
[_data_relations:protected] => Array
(
)
[_original_relations:protected] => Array
(
)
[_reset_relations:protected] => Array
(
)
[_disabled_events:protected] => Array
(
)
[_view:protected] =>
[_iterable:protected] => Array
(
)
)
答案 0 :(得分:0)
好好玩了一段时间后,我找到了一个修复,使用FuelPHP的内置类之一,Format;
Format::forge($entry)->to_array();
将执行转换,然后对响应的数组进行json_encode。这是我使用FuelPHP ORM将json编码的字符串发送回用户的完整方法:
public function get_product()
{
$product_id = Uri::segment(4);
$response = new Response();
try{
if($product_id == null){
throw new Exception('No product ID given');
}else{
$entry = Model_V1_Inventory::find($product_id);
$entry = Format::forge($entry)->to_array();
$response->body(json_encode($entry));
$response->set_status(200);
return $response;
}
}catch(Exception $e){
$response->body(json_encode(['Status' => 400, 'Message' => $e->getMessage()]));
$response->set_status(400);
return $response;
throw new Exception($e);
}
}
答案 1 :(得分:0)
您也可以使用$entry->to_array()
,不需要Format
课程。
https://github.com/fuel/orm/blob/fc4f27af2cc55e99c435d490d0af69fabda70cb7/classes/model.php#L2028