Question

需要有关复杂查询的帮助。服务器接收一些用于查询的参数，而该查询正在序列化为json。我需要为每个任务添加平均等级（因此可以从json.item [i] .rating访问该字段）并对其进行排序。

还有一件事：是否有更好的方法来保持db的平均评级？我觉得一直计算评分并不是一个好主意。

PS：对于空检查，btw switch case更快？

//some params

$repository = $this->getDoctrine()->getRepository('AppBundle:Quest');
        $qb = $repository->createQueryBuilder('q')
            ->innerJoin('q.city', 'c')
            ->where('c.id = :city_id')
            ->setParameter('city_id', $cityId);

        if($minPlayers != null){
            $qb ->andWhere('q.minplayers >= :minplayers')
                ->setParameter('minplayers', $minPlayers);
        }
        if($maxPlayers != null){
            $qb ->andWhere('q.maxplayers <= :maxplayers')
                ->setParameter('maxplayers', $maxPlayers);
        }
        if($tagsId != null){
            $qb ->innerJoin('q.tags','t')
                ->andWhere('t.id IN (:tags)')
                ->setParameter(':tags', implode(",", $tagsId));
        }
        if($organizerId != null){
            $qb ->andWhere('q.organizer = :organizer_id')
                ->setParameter('organizer_id', $organizerId);
        }
        if($ispremium != null){
            $qb ->andWhere('q.ispremium = :isPremium')
                ->setParameter('isPremium', $ispremium)
                ->addOrderBy('q.premiumorder', 'ASC');
        }
        $qb ->setFirstResult($FirstResult)
            ->setMaxResults($MaxResults);


        $query = $qb->getQuery();

        $paginator = new Paginator($query, $fetchJoinCollection = true);
        $c = count($paginator);

        $result = $query->getResult();

        $serializer = $this->get('jms_serializer');
        $data = $serializer->serialize($result, 'json',
            SerializationContext::create()
                ->enableMaxDepthChecks()
                ->setGroups(array('questSearch'))
        );

        $json ='{"total_count":'.$c.',"items":'.$data.',"amountOfelems":'.$amountOfelems.',"citySlug":'.json_encode($citySlug).',"userId":'.json_encode($userId).'}';

        return new JsonResponse($json);

实体：

class Quest{
...
 /**

     * @OneToMany(targetEntity="AppBundle\Entity\Comment", mappedBy="quest")
     */
    protected $comments;
}



class Comments{
/**
     * @ORM\Column(type="integer")
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    protected $id;
/**
     * @ORM\Column(type="integer")
     */
    protected $rating;
 /**
     * @ORM\ManyToOne(targetEntity="AppBundle\Entity\Quest", inversedBy="comments")
     * @ORM\JoinColumn(name="quest_id", referencedColumnName="id")
     */
    protected $quest;
}

Answer 1

最简单的方法（也是整体表现的最佳方式）是将Quest的评分存储在任务表中，并在每次编辑/添加Comment时刷新它。你可以使用Doctrine Events。

这可以解决您的问题，因为这样您就不必在每个请求中计算，并且当您要求任务表时，评级将自动被选中。

Doctrine querybuilder复杂规则

1 个答案: