我在json中有这个对象,我想用json架构验证
"reference": {
"lookup" : "opportunity",
"shortreference": 93671,
"guid": "4bb30c46-20ec-e511-9408-005056862bfb"
}
查找属性是必需的,然后我至少需要短引用或 guid 或两者兼而有之。
{
"reference": {
"type": "object",
"description": "opportunity reference",
"properties": {
"lookup": {
"enum": [
"employee",
"opportunity",
"serviceline",
"account"
]
}
},
"anyOf": [
{
"properties": {
"shortreference": {
"type": "integer"
},
"guid": {
"type": "string"
}
}
}
],
"required": [
"lookup"
]
}
}
修改 我使用以下架构修复了我的问题
{
"reference": {
"type": "object",
"required": [
"lookup"
],
"properties": {
"lookup": {
"type": "string",
"enum" : ["opportunity", "employee", "serviceline", "account"]
}
},
"anyOf": [
{
"properties": {
"shortreference": {
"type": "integer"
}
},
"required": [
"shortreference"
]
},
{
"properties": {
"crmguid": {
"type": "string"
}
},
"required": [
"crmguid"
]
},
{
"properties": {
"springim": {
"type": "integer"
}
},
"required": [
"springim"
]
}
]
}
但是当我同时拥有这两个元素时,所有输入类型都没有输入: 如果“shortreference”:“12345”(字符串而不是整数),只要提供参数crmguid,就不会执行有关类型的检查。有没有办法强迫它。 (我正在使用AJV:https://github.com/epoberezkin/ajv)
答案 0 :(得分:4)
anyOf
会在找到一个匹配的架构后立即停止验证。如果您将所有属性声明提取到模式的根目录并且required
模式中只有anyOf
,它应该按预期工作。这样,所有属性都将进行类型检查,anyOf
将在找到至少一个必需属性时停止验证。
{
"reference": {
"type": "object",
"required": ["lookup"],
"properties": {
"lookup": {
"type": "string",
"enum" : ["opportunity", "employee", "serviceline", "account"]
},
"shortreference": { "type": "integer" },
"crmguid": { "type": "string" },
"springim": { "type": "integer" }
},
"anyOf": [
{ "required": ["shortreference"] },
{ "required": ["crmguid"] },
{ "required": ["springim"] }
]
}
}