Question

ExpandoObject是否有任何便利工厂方法？有点像，我不知道，

dynamic disney = new ExpandoObject("First", "Donald", "Last", "Duck");

Answer 1

不，没有，但你可以在几分钟内写出来。 :) 你走了：

C＃

class Program
{
    static void Main(string[] args)
    {
        dynamic ex = ExpandoFactory.Create("First", "Donald", "Last", "Duck");
        Console.WriteLine(ex.First);
        Console.WriteLine(ex.Last);
    }
}

static class ExpandoFactory
{
    internal static ExpandoObject Create(params string[] items)
    {
        //safety checks omitted for brevity
        IDictionary<string, object> result = new ExpandoObject();
        for (int i = 0; i < items.Length; i+=2)
        {
            result[items[i]] = items[i + 1];
        }
        return result as ExpandoObject;
    }
}

当然，您应该事先检查阵列的基数。我希望这会有所帮助。

ExpandoObject便利工厂？

1 个答案: