Question

想象一下，你有以下字符串：

"badger randomword badger mushroom mushroom somethingelse"

我想保留“獾”和“蘑菇”这两个词，并用“蘑菇”取代所有其他词：

"badger mushroom badger mushroom mushroom mushroom"

但是我找不到正则表达式来匹配“除了獾和蘑菇之外的所有东西”。你能救我吗？

Answer 1

这将有效

(?!\bbadger\b|\bmushroom\b)\b[^\s]+\b

<强> Regex Demo

Python代码

p = re.compile(r'(?!\bbadger\b|\bmushroom\b)\b[^\s]+\b')
test_str = "badger randomword badger mushroom mushroom somethingelse"
subst = "mushroom"
result = re.sub(p, subst, test_str)

<强> Ideone Demo

Answer 2

执行此任务的简单非正则表达式oneliner将是 -

new_string = ' '.join(word if word == 'badger' else 'mushroom' for word in original_string.split())

我建议不要在Python中使用复杂的正则表达式，因为Beautiful Is Better Than Ugly。

Answer 3

您可以将re.sub与函数参数一起使用，这将使模式非常简单：

import re

s = "badger randomword badger mushroom mushroom somethingelse"
re.sub('\w+', lambda x: 'badger' if x.group(0) == 'badger' else 'mushroom', s)

Answer 4

非正则表达式解决方案（并且更容易阅读）是这样的：

oldstring = "badger randomword badger mushroom mushroom somethingelse"
newstring = ""

for part in oldstring.split(" "):
    if part in ["badger", "mushroom"]:
        newstring += part
    else:
        newstring += "mushroom"
    newstring += " "

newstring = newstring[:-1]

Answer 5

试试这个

(?!badger\b)\b\w+\b

Regex demo

<强>解释
(?!…)：否定前瞻sample
\：逃脱一个特殊字符sample
\w：“单词字符”：ASCII字母，数字或下划线sample
+：一个或多个sample

的Python

import re
p = re.compile(ur'(?!badger\b)\b\w+\b')
test_str = u"badger randomword badger mushroom mushroom somethingelse"
subst = u"mushroom"

result = re.sub(p, subst, test_str)#badger mushroom badger mushroom mushroom mushroom

Python正则表达式 - 替换所有单词

5 个答案: