下面是我试图验证表中是否存在相同名称id
和email
的脚本,问题是即使我为每个字段添加新输入我仍然存在"数据已存在",如何解决此问题,以及如何使用正则表达式验证每个字段。对于id
,我需要使用正则表达式的三个字母和3个数字。
if(isset($_POST['register'])){
//Retrieve the field values from our registration form.
$name = !empty($_POST['name']) ? trim($_POST['name']) : null;
$ccode = !empty($_POST['id']) ? trim($_POST['id']) : null;
$email = !empty($_POST['email']) ? trim($_POST['email']) : null;
$sql = "SELECT COUNT(*) AS num FROM users";
$stmt = $pdo->prepare($sql);
$stmt->bindValue(':name', $name);
$stmt->bindValue(':id', $id);
$stmt->bindValue(':email', $email);
$stmt->execute();
$row = $stmt->fetch(PDO::FETCH_ASSOC);
if($row['num'] > 0){
die('The Data already exists!');
} else {
$sql = "INSERT INTO users (name, id, email) VALUES (:name, :id, :email)";
$stmt = $pdo->prepare($sql);
$stmt->bindValue(':name', $name);
$stmt->bindValue(':id', $id);
$stmt->bindValue(':email', $email);
$result = $stmt->execute();
if ($result) {
echo 'User aadded successfully!';
}
}
}
<form action="sign.php" method="post">
<label for="name">Name</label>
<input type="text" id="name" name="name" required><br>
<label for="id">id</label>
<input type="text" id="" name="id" required><br>
<label for="email">Email</label>
<input type="email" id="email" name="email" required><br>
<input type="submit" name="register" value=" Click to Add"></button>
</form>
以及如何验证字段是否具有相同名称。例如,我有3个输入字段,在第一个字段中我输入一个人的名字,在第二个或第三个字段中,如果我输入相同的名称,当我点击提交按钮时应显示错误,是否可以使用for来完成循环以检查每个字段是否包含相同的名称。
答案 0 :(得分:0)
您可以尝试: -
$name = ($_POST['name']) ? $name = trim($_POST['name']) : $name='';
答案 1 :(得分:0)
uuhm,你检查那些变量是否已经存在的行不使用任何变量吗?
$sql = "SELECT COUNT(*) AS num FROM users"; // Where are the variables?
$stmt = $pdo->prepare($sql);
$stmt->bindValue(':name', $name);
$stmt->bindValue(':id', $id);
$stmt->bindValue(':email', $email);
$stmt->execute();
您想要做的是:
$sql = "SELECT COUNT(*) AS num FROM users WHERE name = :name OR id = :id OR email = :email"; // Where are the variables?
$stmt = $pdo->prepare($sql);
$stmt->bindParam(':name', $name);
$stmt->bindParam(':id', $id);
$stmt->bindParam(':email', $email);
$stmt->execute();
我对使用PDO不是很有经验。我更喜欢MySQLi
您应该阅读有关prepared statements
的更多信息编辑:
基于评论的新查询,只需在PHP中检查名称/经理/高级中的双打:
if($name != $manager && $manager != $senior && $name != $senior) {
$sql = "SELECT COUNT(*) AS num FROM users WHERE (name = :name OR manager = :manager OR senior = :senior)";
$stmt = $pdo->prepare($sql);
$stmt->bindParam(':name', $name);
$stmt->bindParam(':manager', $manager);
$stmt->bindParam(':senior', $senior);
$stmt->execute();
// insert other stuff
} else {
// insert error here
}
完整代码:
if(isset($_POST['register'])){
//Retrieve the field values from our registration form.
$name = !empty($_POST['name']) ? trim($_POST['name']) : null;
$manager= !empty($_POST['manager']) ? trim($_POST['manager']) : null;
$senior= !empty($_POST['senior']) ? trim($_POST['senior']) : null;
if($name != $manager && $manager != $senior && $name != $senior) {
$sql = "SELECT COUNT(*) AS num FROM users WHERE (name = :name OR manager = :manager OR senior = :senior)";
$stmt = $pdo->prepare($sql);
$stmt->bindParam(':name', $name);
$stmt->bindParam(':manager', $manager);
$stmt->bindParam(':senior', $senior);
$stmt->execute();
$row = $stmt->fetch(PDO::FETCH_ASSOC);
if($row['num'] > 0){
die('The Data already exists!');
} else {
$sql = "INSERT INTO users (name, manager, senior) VALUES (:name, :manager, :senior)";
$stmt = $pdo->prepare($sql);
$stmt->bindParam(':name', $name);
$stmt->bindParam(':manager', $manager);
$stmt->bindParam(':senior', $senior);
$result = $stmt->execute();
if ($result) {
echo 'User added successfully!';
}
}
} else {
die('Duplicate in name/manager/senior!');
}
}
答案 2 :(得分:0)
您需要从
更新以下查询行$sql = "SELECT COUNT(*) AS num FROM users";
$stmt = $pdo->prepare($sql);
到这个
$sql = "SELECT COUNT(*) AS num FROM users WHERE name = :name OR id = :id OR email = :email";
$stmt = $pdo->prepare($sql);