Spring Data JPA在运行测试时无法识别我的实体。请在下面找到代码。我们不使用Spring启动。
JPA配置文件（JPAConfigration_Test.xml）
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/data/jpa
http://www.springframework.org/schema/data/jpa/spring-jpa.xsd">
<!--Configing Core JPA Repositories-->
<jpa:repositories base-package="org.test.repository" entity-manager-factory-ref="entityManagerFactory_core" transaction-manager-ref="transactionManager"/>
<!-- Configring Core Data Resource-->
<bean id="DS_TEST" class="org.springframework.jndi.JndiObjectFactoryBean" scope="singleton">
<property name="jndiName" value="java:comp/env/jdbc/ladvice_service" />
<property name="resourceRef" value="true" />
</bean>
<!--Configring Core System Entity Manager-->
<bean id="entityManagerFactory_core" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceXmlLocation" value="classpath:config/persistence.xml" />
<property name="persistenceUnitName" value="LA_Persistence" />
<property name="dataSource" ref="DS_TEST" />
<property name="packagesToScan" value="org.test.model" />
<property name="jpaProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.Oracle10gDialect</prop>
<!-- always puts logging out to the console...we want it in the log file -->
<prop key="hibernate.connection.show_sql">false</prop>
<prop key="hibernate.hbm2ddl.auto">none</prop>
<prop key="hibernate.cache.provider_class">org.hibernate.cache.NoCacheProvider</prop>
<prop key="hibernate.cache.use_second_level_cache">false</prop>
<prop key="hibernate.cache.use_structured_entries">true</prop>
<prop key="hibernate.cache.use_query_cache">false</prop>
<prop key="hibernate.generate_statistics">true</prop>
<prop key="hibernate.default_batch_fetch_size">500</prop>
<prop key="hibernate.max_fetch_depth">5</prop>
<prop key="hibernate.jdbc.batch_size">1000</prop>
<prop key="hibernate.use_outer_join">true</prop>
</props>
</property>
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="false" />
<property name="databasePlatform" value="org.hibernate.dialect.Oracle10gDialect" />
</bean>
</property>
</bean>
<!--Confirgring Core Transaction Manager-->
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory_core" />
</bean>
</beans>
存储库
public interface DemoRepository extends JpaRepository<Demo, Integer> {}
实体
@Entity
@Table(schema="TESTUSER1")
public class Demo {
@Id
private Integer id;
@Column
private String description;
}
持久性
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="LA_Persistence">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<properties>
<property name="hibernate.cache.provider_class" value="org.hibernate.cache.NoCacheProvider"/>
<property name="hibernate.show_sql" value="false"/>
<property name="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect"/>
<property name="hibernate.cache.use_second_level_cache" value="false"/>
<property name="hibernate.cache.use_query_cache" value="false"/>
</properties>
</persistence-unit>
</persistence>
测试
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations={"classpath:spring/JPAConfigration_Test.xml"})
public class LegalRequestRepositoryTest{
@BeforeClass
public static void initiateJNDI() throws IllegalStateException, NamingException{
SimpleNamingContextBuilder builder = new SimpleNamingContextBuilder();
BasicDataSource basicDataSourceLAdvice = new BasicDataSource();
basicDataSourceLAdvice.setDriverClassName("oracle.jdbc.OracleDriver");
basicDataSourceLAdvice.setUsername("TESTUSER1");
basicDataSourceLAdvice.setPassword("TESTUSER1");
basicDataSourceLAdvice.setUrl("jdbc:oracle:thin:@localhost:1521:XE");
builder.bind( "java:comp/env/jdbc/ladvice_service" , basicDataSourceLAdvice );
builder.activate();
}
@Test
public void testDEMO(){
}
}
无法加载应用程序上下文。我得到的错误是
at org.springframework.test.context.DefaultCacheAwareContextLoaderDelegate.loadContext(DefaultCacheAwareContextLoaderDelegate.java:86) ~[spring-test-4.1.6.RELEASE.jar:4.1.6.RELEASE]
... 26 common frames omitted
Caused by: java.lang.IllegalArgumentException: Not an managed type: class org.test.model.Demo
at org.hibernate.ejb.metamodel.MetamodelImpl.managedType(MetamodelImpl.java:200) ~[hibernate-entitymanager-4.2.7.Final.jar:4.2.7.Final]
at org.springframework.data.jpa.repository.support.JpaMetamodelEntityInformation.<init>(JpaMetamodelEntityInformation.java:68) ~[spring-data-jpa-1.7.3.RELEASE.jar:na]
at org.springframework.data.jpa.repository.support.JpaEntityInformationSupport.getMetadata(JpaEntityInformationSupport.java:67) ~[spring-data-jpa-1.7.3.RELEASE.jar:na]
at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getEntityInformation(JpaRepositoryFactory.java:145) ~[spring-data-jpa-1.7.3.RELEASE.jar:na]
at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getTargetRepository(JpaRepositoryFactory.java:89) ~[spring-data-jpa-1.7.3.RELEASE.jar:na]
at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getTargetRepository(JpaRepositoryFactory.java:69) ~[spring-data-jpa-1.7.3.RELEASE.jar:na]
at org.springframework.data.repository.core.support.RepositoryFactorySupport.getRepository(RepositoryFactorySupport.java:173) ~[spring-data-commons-1.9.3.RELEASE.jar:na]
at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.initAndReturn(RepositoryFactoryBeanSupport.java:239) ~[spring-data-commons-1.9.3.RELEASE.jar:na]
at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.afterPropertiesSet(RepositoryFactoryBeanSupport.java:225) ~[spring-data-commons-1.9.3.RELEASE.jar:na]
at org.springframework.data.jpa.repository.support.JpaRepositoryFactoryBean.afterPropertiesSet(JpaRepositoryFactoryBean.java:92) ~[spring-data-jpa-1.7.3.RELEASE.jar:na]
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1633) ~[spri
我能够连接到数据库，表格确实存在。为什么会这样？
更新1
如果在<class>中将实体添加为Persistence.xml，这似乎有效。问题似乎与packagesToScan
LocalContainerEntityManagerFactoryBean有关
答案 0 :(得分：3)
仅在LocalContainerEntityManagerFactory上定义 no 持久性单元时才使用扫描实体。您定义了一个不包含任何持久化类的持久性单元，以便Hibernate最终知道没有任何类。
您完整persistence.xml似乎是多余的，因为您只需复制LCEMFB上已有的配置。我建议删除它，让Spring扫描实体。