我在为 Oracle 12c编写的查询中遇到了非常糟糕的表现。这可能与我对连接的低效使用有关,并且希望有人可以帮助我解决我出错的地方。我的查询目前需要一分钟才能运行。
我正在尝试将表和列名称返回到:
目前我的查询内容如下
SELECT consCols.table_name, consCols.column_name
FROM all_cons_columns consCols
INNER JOIN all_constraints cons
ON cons.constraint_name = consCols.constraint_name
INNER JOIN all_tab_columns cols
ON consCols.table_name = cols.table_name AND consCols.column_name = cols.column_name
WHERE cons.constraint_type = 'P'
AND cons.owner = 'MY_OWNER'
AND cols.data_type = 'NUMBER'
AND consCols.table_name IN(
SELECT consCols2.table_name
FROM all_cons_columns consCols2
INNER JOIN all_constraints cons2
ON cons2.constraint_name = consCols2.constraint_name
WHERE cons2.constraint_type = 'P'
AND cons2.owner = 'MY_OWNER'
GROUP BY consCols2.table_name
HAVING COUNT(consCols2.table_name) = 1
);
感谢您提供任何帮助。
答案 0 :(得分:3)
使用分析函数会加快查询速度吗?
$scope.checkJob= function(data) {
//your logic
};
甚至聚合?
SELECT table_name, column_name
FROM (SELECT consCols.table_name, consCols.column_name, cols.data_type,
COUNT(*) OVER (PARTITION BY consCols.table_name) as cnt
FROM all_cons_columns consCols INNER JOIN
all_constraints cons
ON cons.constraint_name = consCols.constraint_name INNER JOIN
all_tab_columns cols
ON consCols.table_name = cols.table_name AND consCols.column_name = cols.column_name
WHERE cons.constraint_type = 'P' AND
cons.owner = 'MY_OWNER'
) tc
WHERE data_type = 'NUMBER' AND cnt = 1;
这是第三种选择:
SELECT consCols.table_name, consCols.column_name
FROM all_cons_columns consCols INNER JOIN
all_constraints cons
ON cons.constraint_name = consCols.constraint_name INNER JOIN
all_tab_columns cols
ON consCols.table_name = cols.table_name AND consCols.column_name = cols.column_name
WHERE cons.constraint_type = 'P' AND
cons.owner = 'MY_OWNER'
GROUP BY consCols.table_name, consCols.column_name
HAVING COUNT(*) = 1 AND
MAX(cols.data_type) = 'NUMBER';
这消除了聚合,查找应该相对较快。