基本上,我有两个实体,地点和事件:
/**
* Place
*
* @ORM\Table(name="place")
* @ORM\Entity(repositoryClass="AppBundle\Repository\PlaceRepository")
*/
class Place
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @ORM\OneToMany(targetEntity="AppBundle\Entity\Event", mappedBy="place")
*/
private $events;
}
和
class Event
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var \DateTime
* @JMS\Type("DateTime<'H:i'>")
* @ORM\Column(name="event_starts", type="datetime")
*/
private $eventStarts;
/**
* @var \DateTime
* @JMS\Type("DateTime<'Y/m/d H:i'>")
* @ORM\Column(name="event_ends", type="datetime", nullable=true)
*/
private $eventEnds;
/**
* @var string
*
* @ORM\Column(name="title", type="string", length=255)
*/
private $title;
/**
* @var string
*
* @ORM\Column(name="event_id", type="string", length=70)
*/
private $event_id;
/**
* @JMS\Exclude()
* @ORM\ManyToOne(targetEntity="Place")
* @ORM\JoinColumn(name="place_id", referencedColumnName="id")
*/
private $place;
当我查询Places时,我希望并非所有事件都会被加入,而只会加入今天发生的事件(eventStarts =今天)。有没有办法只用Doctrine或MySQL呢?
答案 0 :(得分:1)
非常简单。
$qb = $this->getEntityManager()->createQueryBuilder();
如果您只想获得在特定日期范围内有活动的地点:
$data = $qb->select('p, e')
->from('YourBundle:Place', 'p')
->join('p.events', 'e')
->where($qb->expr()->between('e.eventStarts', ':start', ':end'))
->setParameter('start', $someStartDateTimeObject)
->setParameter('end', $someEndDateTimeObject)
->getQuery()
->getResult();
如果您希望获得所有地点,即使他们没有活动,但如果有指定范围内的活动,请加入活动:
$data = $qb->select('p, e')
->from('YourBundle:Place', 'p')
->leftJoin('p.events', 'e', 'WITH', $qb->expr()->between('e.eventStarts', ':start', ':end'))
->setParameter('start', $someStartDateTimeObject)
->setParameter('end', $someEndDateTimeObject)
->getQuery()
->getResult();