Question

首次使用该网站提出问题我对Chrome扩展程序不熟悉，所以我确定我犯了一些错误我提前道歉

我要通过邮寄请求发送当前标签的网址，我只能通过提交发送网址如何在页面加载中自动发送

这是我的代码

的manifest.json

       {
      "manifest_version": 2,

      "name": "Phishing tool",
      "description": "This extension send url to server to check for phishing",
      "version": "1.0",

      "browser_action": {
        "default_icon": "icon.png",
        "default_popup": "popup.html"
      },
      "permissions": [
        "activeTab",
        "tabs",
        "http://localhost:8080/ph/FirstServlet*"
        ]
    }

popup.html

<!DOCTYPE html>
<html>
<head><script src="p.js"></script></head>
<body>
<object width="200" height="50" ></object>

<form action="http://localhost:8080/ph/FirstServlet" method="POST">


link:<input type="text" name="first_name"> <br /><br />
<input  type="submit" value="Submit" />
</form>
<p>
<button id="myBtn"> click here to display the url</button> </p>
<h1 id="demo">Url displays Here</h1>
</body>
</html>

p.js

    document.addEventListener("DOMContentLoaded", function() {
    chrome.tabs.query({currentWindow: true, active: true}, function(tabs) {
        var tabURL = tabs[0].url;

        var xhr = new XMLHttpRequest();
        xhr.onload = function(){
              console.log(xhr.responseText);
        };
        xhr.open("POST", "http://localhost:8080/ph/FirstServlet");
        xhr.send(tabURL);
    });
});

我尝试了但是当我点击插件图标时它没有显示来自服务器的响应

Answer 1

假设您要将弹出式页面（扩展程序）中的网址发送到您的服务器，而您的服务器网址为SERVER_URL，则需要执行以下操作：

在SERVER_URL文件的permissions字段中添加manifest.json，对于您的情况，它将是
```
"permissions": [
    "http://localhost:8080/ph/FirstServlet/*"
]
```

在popup.js

中拨打ajax电话

document.addEventListener("DOMContentLoaded", function() {
    chrome.tabs.query({currentWindow: true, active: true}, function(tabs) {
        var tabURL = tabs[0].url;
        var formData = new FormData();
        formData.append("first_name", tabURL);

        var xhr = new XMLHttpRequest();
        xhr.onload = function(){
            console.log(xhr.responseText);
            // Your logic
        };

        xhr.open("POST", SERVER_URL);
        xhr.send(formData);
    });
});

通过Chrome扩展程序

1 个答案: