无法使用Blowfish解密

Question

我正在使用Python3和PyCrypto模块进行Blowfish算法。当我通过命令行提供密钥和明文但我无法解密时，我能够加密。但是，如果我在Python Interpreter中使用它，代码就能正常工作。

ENCRYPTION（blowfish_encr.py）

ORDER BY

DECRYPTION（blowfish_decr.py）

from Crypto.Cipher import Blowfish
from Crypto import Random
from struct import pack
import sys

bs = Blowfish.block_size
key = sys.argv[1].encode()
iv = Random.new().read(bs)
cipher = Blowfish.new(key, Blowfish.MODE_CBC, iv)

plaintext = sys.argv[2].encode()
plen = bs - divmod(len(plaintext),bs)[1]
padding = [plen]*plen
padding = pack('b'*plen, *padding)

msg = iv + cipher.encrypt(plaintext + padding)
print(msg)

输出：

  

$ python3 blowfish_encr.py key'Test it！'

from Crypto.Cipher import Blowfish
from struct import pack
import sys

bs = Blowfish.block_size
ciphertext = sys.argv[2].encode()
key = sys.argv[1].encode()

iv = ciphertext[:bs]
ciphertext = ciphertext[bs:]
cipher = Blowfish.new(key, Blowfish.MODE_CBC, iv)
msg = cipher.decrypt(ciphertext)
last_byte = msg[-1]

msg = msg[:- (last_byte if type(last_byte) is int else ord(last_byte))]
print(repr(msg))

  

$ python3 blowfish_decr.py key'\ xf8 \ x1eK）\ x81？\ xa2 \ x88 \ x01 \ x16 \ x8e \ xdc \ xe5 \ xb9 \ xd8_K \ xce \ x03 \ xe4 \ x88g \ xf8 \ xa1'< / p>

b'\xf8\x1eK)\x81?\xa2\x88\x01\x16\x8e\xdc\xe5\xb9\xd8_K\xce\x03\xe4\x88g\xf8\xa1'

如何解密？我知道错误是因为当我将编码文本作为字符串输入时，它将所有 File "blowfish_decr.py", line 12, in <module> msg = cipher.decrypt(ciphertext) File "/usr/lib/python3/dist-packages/Crypto/Cipher/blockalgo.py", line 295, in decrypt return self._cipher.decrypt(ciphertext) ValueError: Input strings must be a multiple of 8 in length 转换为\，当我尝试\\时，它不起作用，因为{{1是} sys.argv[2].encode().replace('\\','\')。

如何使用命令行参数完成它？