当我尝试更新数据库时,属性Childrens
未保存,SortOrder
和显示名称都是成功的。
这是我的模特:
[Key]
[DatabaseGenerated(DatabaseGeneratedOption.Identity)]
public Int64 Id { get; set; }
public Int64? LanguageId { get; set; }
[ForeignKey("LanguageId")]
public Language Language { get; set; }
public int SortOrder { get; set; }
public string DisplayName { get; set; }
[ForeignKey("Childrens")]
public Int64? ParentId { get; set; }
public ICollection<Menu> Childrens { get; set; }
我用新参数调用了这个函数:
public void SaveMenu(List<Menu> newMenu)
{
foreach(Menu _addMenu in newMenu)
{
this.Update(_addMenu);
}
this.Commit();
}
public void Update(T entity)
{
try
{
DbEntityEntry _dbEntityEntry = this.DbContext.Entry(entity);
DbContext.Entry(entity).State = EntityState.Modified;
if (_dbEntityEntry.State == EntityState.Detached)
this.dbSet.Attach(entity);
_dbEntityEntry.State = EntityState.Modified;
}
}
public bool Commit()
{
try
{
this.DbContext.SaveChanges();
}
catch (Exception ex)
{
return false;
}
return true;
}
孩子们并没有改变,而是改变了改变的成功。
为什么会这样?
编辑:
我找到解决方案的问题是因为子对象是虚拟的,需要从数据库中获取“真实”对象
public void SaveMenu(List<Menu> newMenu)
{
foreach(Menu _addMenu in newMenu)
{
List<Menu> listMenu = new List<Menu>();
foreach (Menu child in _addMenu.Childrens)
{
Menu _menuFromDB = this.Query().FirstOrDefault(s => s.Id == child.Id);
_menuFromDB.SortOrder = child.SortOrder;
listMenu.Add(_menuFromDB);
}
_addMenu.Childrens = listMenu;
this.Update(_addMenu,null);
}
this.Commit();
}