Question

我有一个简单的事实Java项目，可以生成随机事实。单击随机按钮时，我想显示一个随机事实，并找到该事实编号。

String factNumber[] = {
            "Fact 1",
            "Fact 2",
            "Fact 3",
            "Fact 4",
            "Fact 5",
};

public String randomButtonNumber() {
            return factNumber[i];
        }

String facts[] = {"Elephants are the only mammals that can't jump.",
            "Candles will burn longer and drip less if they are placed in the freezer a few hours before using.",
            "Potatoes have more chromosomes than humans.",
            "You burn more calories sleeping than you do watching television.",
            "Animals that lay eggs don't have belly buttons.",
};

public String randomButton() {
        Random random = new Random();
        i = random.nextInt(facts.length);
        return facts[random.nextInt(facts.length)];
    }

现在，我的代码生成一个随机事实，但事实数字保持在1。

Answer 1

您正在生成两个不同的数字。只需使用i

即可

 i = random.nextInt(facts.length);
 return facts[i];

Answer 2

试试这个：

public String randomButton() {
    Random random = new Random();
    i = random.nextInt(facts.length);
    return facts[i];
}

Answer 3

这可以解决您的问题。每次你进行random.next（facts.length）调用时，它会得到两个随机数，并且它们相同的概率较小

public String randomButton() {
    Random random = new Random();
    return facts[random.nextInt(facts.length)];
}

Answer 4

buf = 'original'

def change_buf(new_val):
    global buf
    buf = new_val

生成随机数组值Java

4 个答案: