每当我执行我的宏(下面)搜索输入搜索框的字符串时,我都会收到运行时错误' 1004'。 Range类的AutoFilter方法失败。我已经尝试在这里寻找这个问题的答案了一段时间,但似乎没有什么能为我提供解决方案。
当我点击' Debug'它突出显示了代码的以下部分。
DataRange.AutoFilter _
Field:=myField, _
Criteria1:=SearchString, _
Operator:=xlAnd
我意识到这不是很多信息,但任何帮助都会非常感激。
P.S。我是VBA的一个完整的新手,并从一个网站上复制了代码,该网站分步指导了在Excel中创建搜索过滤器。
Sub SearchBox()
Dim myButton As OptionButton
Dim SearchString As String
Dim ButtonName As String
Dim sht As Worksheet
Dim myField As Long
Dim DataRange As Range
Dim mySearch As Variant
'Load Sheet into A Variable
Set sht = ActiveSheet
'Unfilter Data (if necessary)
On Error Resume Next
sht.ShowAllData
On Error GoTo 0
'Filtered Data Range (include column heading cells)
Set DataRange = sht.Range("A5:Z40000") 'Cell Range
'Set DataRange = sht.ListObjects("Table1").Range 'Table
'Retrieve User's Search Input
mySearch = sht.Shapes("UserSearch").TextFrame.Characters.Text 'Control Form
'mySearch = sht.OLEObjects("UserSearch").Object.Text 'ActiveX Control
'mySearch = sht.Range("A1").Value 'Cell Input
'Determine if user is searching for number or text
If IsNumeric(mySearch) = True Then
SearchString = "=" & mySearch
Else
SearchString = "=*" & mySearch & "*"
End If
'Loop Through Option Buttons
For Each myButton In sht.OptionButtons
If myButton.Value = 1 Then
ButtonName = myButton.Text
Exit For
End If
Next myButton
'Determine Filter Field
On Error GoTo HeadingNotFound
myField = Application.WorksheetFunction.Match(ButtonName, DataRange.Rows(1), 0)
On Error GoTo 0
'Filter Data
DataRange.AutoFilter _
Field:=myField, _
Criteria1:=SearchString, _
Operator:=xlAnd
'Clear Search Field
sht.Shapes("UserSearch").TextFrame.Characters.Text = "" 'Control Form
'sht.OLEObjects("UserSearch").Object.Text = "" 'ActiveX Control
'sht.Range("A1").Value = "" 'Cell Input
Exit Sub
'ERROR HANDLERS
HeadingNotFound:
MsgBox "The column heading [" & ButtonName & "] was not found in cells " & DataRange.Rows(1).Address & ". " & _
vbNewLine & "Please check for possible typos.", vbCritical, "Header Name Not Found!"
End Sub
答案 0 :(得分:0)
检查myField
的值,它必须介于1到26之间,因为您的范围是A - > ž。