Question

I have a codeigniter file in controller . I want to pass parameter in constructor from ajax using jquery . How can pass value in $action ???

function __construct($action)
{
    $this->json['status']=false;
    if (preg_match("/json/i", $_SERVER['HTTP_ACCEPT'], $match))
        $this->requestType = "JSON";
    switch ($action) {
        case 'login': $this->login($_REQUEST);break;
        case 'addSocialPages': $this->setSocialLinks($_REQUEST);break;
        case 'get_info': $this->setSocialinfo($_REQUEST);break;
        case 'loginfromfront': $this->loginFront($_REQUEST);break;
        default:
            # code...
            break;
    }
    if($this->requestType=="JSON")
        echo json_encode($this->json);
}

Answer 1

你不能真的这样做。
控制器由核心系统构建，您无法在初始化时触摸它们的构造函数（核心代码：$ CI = new $ class（）; //调用时没有参数）。构造函数更倾向于初始化事物而不是为了努力工作。

顺便说一句，你的概念并没有用（在构造函数中做所有事情）。

CodeIgniter有自己的方式来运行/处理请求，如下所示：

class Default extends CI_Controller {

    protected function send_json_output($response) {
        $this->output->set_content_type('application/json');
        echo json_encode($response);
    }

    public function login() {
        $username = $this->input->post('username');
        $password = $this->input->post('password');
        // your login code
        $response = array('succes' => true);
        $this->send_json_output($response);
    }
    public function get_info() {
        $user_id = $this->input->post('user_id');
        // your get_info code
        $user_name = $this->get_username_by_id($user_id);
        $response = array('username' => $user_name);
        $this->send_json_output($response);
    }
    public function login_from_front() {
        // your login_from_front code
    }


}

JS

// call the login action:
jQuery.post(
    '<?php echo site_url('default/login'); ?>',
    {username:'frank', password:1234},
    function(data) {
        if(data.success) {
            alert('You are logged in');
        }
    },
    'json'
);

// call the get_info action:
jQuery.post(
    '<?php echo site_url('default/get_info'); ?>',
    {user_id:123},
    function(data) {
        alert(data.username);
    },
    'json'
);

How can i Pass constructor parameter in codeigniter via Jquery ajax

1 个答案: