Question

首先感谢耐心阅读这么久的问题。这是迄今为止我可以制作的最短版本。

这个问题是my previous question的子问题。一旦我澄清它，我会更新它并要求重新打开然后我可以回答它

我的问题是nth以下代码组合的实用方法。

我有行程编组的连接航班，其数量为1,2 .. n 每个航班可能有A，B，C等级......

我将每个航班与同一班级相结合

这是我的代码产生组合：

//combination of ONE flightSegments
var firstFlightSegments = flightSegments.Where(s => s.Count == 1).ToList();

var originDestination = 
    (from firstFlightSegment in firstFlightSegments
    select
        new originDestination {
            pnr = Utils.GeneratePnr(),
            flightSegments = new List<FlightSegment>{firstFlightSegment}
        }
    )

//combinations of TWO flightSegments
var firstFlightSegments = flightSegments.Where(s => s.Count == 1).ToList();
var secondSecondSegments = flightSegments.Where(s => s.Count == 2).ToList();

var originDestination = 
    (from firstFlightSegment in firstFlightSegments
        join secondFlightSegment in secondSecondSegments
            on firstFlightSegments.flightClass equals secondSegment.flightClass
    select
        new originDestination {
            pnr = Utils.GeneratePnr(),
            flightSegments = new List<FlightSegment>{firstFlightSegment, secondFlightSegment}
        }
    )

//combinations of THREE flightSegments
var firstFlightSegments = flightSegments.Where(s => s.Count == 1).ToList();
var secondSecondSegments = flightSegments.Where(s => s.Count == 2).ToList();
var thirdFlightSegments = flightSegments.Where(s => s.Count == 3).ToList();

var originDestination = 
    (from firstFlightSegment in firstFlightSegments
        join secondFlightSegment in secondSecondSegments
            on firstFlightSegments.flightClass equals secondSegment.flightClass
                join thirdFlightSegment in thirdFlightSegments 
                    on secondSegment.flightClass equals thirdFlightSegment.flightClass       

    select
        new originDestination {
            pnr = Utils.GeneratePnr(),
            flightSegments = new List<FlightSegment>{firstFlightSegment, secondFlightSegment, thirdFlightSegment}
        }

//HOW TO DO combinations of N flightSegments

???

修改在@Rhumborl回答哪个方面根据上方工作正常之后，我需要添加此代码以反映我需要的内容MyIndex我将在其上进行分组

  var originDestination =   
        (from firstFlightSegment in firstFlightSegments
            join secondFlightSegment in secondSecondSegments
                on firstFlightSegments.flightClass equals secondSegment.flightClass
        select
            new originDestination {
                pnr = Utils.GeneratePnr(),
                myIndex = firstFlightSegment.FligthNumber + secondFlightSegment.FligthNumber
                flightSegments = new List<FlightSegment>{firstFlightSegment, secondFlightSegment}
            }
        )

Answer 1

您希望获得航班的所有航段，并按照其计数顺序将其作为列表返回？

一个简单的GroupBy会这样做：

var flights = fightSegments
    .GroupBy(fs => fs.flightClass)  // get all steps for each flight together
    .Select(fc =>
        new originDestination {
            //flightClass = fc.Key, // if you need this
            pnr = Utils.GeneratePnr(),
            flightSegments = fc         // fc is the list of steps
                .OrderBy(s => s.Count)  // make sure it is in order
                .ToList()
        }
    )

如果您只想要至少有n个步骤的航班，那么您需要做更多的工作来添加额外的where子句：

var flights = fightSegments
    .GroupBy(fs => fs.flightClass)
    .Where(fcg => fcg.Count() >= n) // make sure flight has n+ steps
    .Select(fc =>
        new originDestination {
            //flightClass = fc.Key, // if you need this
            pnr = Utils.GeneratePnr(),
            flightSegments = fc
                .OrderBy(s => s.Count)
                .ToList()
        }
    )

如何加入第n个列表

1 个答案: