Question

SQL 2008

我有两张桌子。一个表（A）具有大约4000个具有lat lng的位置。另一个表（B）具有800个位置，具有lat lng。

我需要表B中的每个lat lng以及15 Km半径内的所有相应的lat lng。

我使用的是sql 2008，对于地理查询来说非常新。

Answer 1

        /*
            Assuming Your tables are like so
        */
        IF OBJECT_ID('#xLocation1') IS NOT NULL
            DROP TABLE #xLocation1
        CREATE TABLE #xLocation1 (
             Id         INT IDENTITY(1,1) CONSTRAINT PK_Location_1 PRIMARY KEY--Reqire this for Geog Spatial Index
            ,LocationId INT
            ,Latitude   FLOAT   NULL
            ,Longitude  FLOAT   NULL
            ,Radius     INT     NULL
            ,GeogPoint  GEOGRAPHY   NULL
        )


        IF OBJECT_ID('#xLocation2') IS NOT NULL
            DROP TABLE #xLocation2
        CREATE TABLE #xLocation2 (
             Id         INT IDENTITY(1,1) CONSTRAINT PK_Location_2 PRIMARY KEY--Reqire this for Geog Spatial Index
            ,LocationId INT
            ,Latitude   FLOAT   NULL
            ,Longitude  FLOAT   NULL
            ,Radius     INT     NULL
            ,GeogPoint  GEOGRAPHY   NULL
        )


        DECLARE @Radius INT = 15 --KM

        /*
            Create GEOGRAPHY POINT datatypes
        */

        UPDATE #xLocation1
        SET
            GeogPoint   = GEOGRAPHY::STGeomFromText('POINT(' + CAST(ISNULL(Longitude,'') AS VARCHAR(20)) + ' ' + CAST(ISNULL(Latitude,'') AS VARCHAR(20)) + ')', 4326)

        UPDATE #xLocation2
        SET
            GeogPoint   = GEOGRAPHY::STGeomFromText('POINT(' + CAST(ISNULL(Longitude,'') AS VARCHAR(20)) + ' ' + CAST(ISNULL(Latitude,'') AS VARCHAR(20)) + ')', 4326)


        /*
            CREATE SPATIAL INDEXes
        */
        CREATE SPATIAL INDEX [SDX_Location1_GeogPoint_x1] ON #xLocation1 ( [GeogPoint] ) 
        USING GEOGRAPHY_GRID 
        WITH 
        (     GRIDS=(LEVEL_1 = HIGH,LEVEL_2 = HIGH,LEVEL_3 = HIGH,LEVEL_4 = HIGH) 
                , CELLS_PER_OBJECT = 64 
                , PAD_INDEX = OFF 
                , SORT_IN_TEMPDB = OFF 
                , DROP_EXISTING = OFF 
                , ALLOW_ROW_LOCKS = ON 
                , ALLOW_PAGE_LOCKS = ON 
        ) 

        CREATE SPATIAL INDEX [SDX_Location2_GeogPoint_x2] ON #xLocation2 ( [GeogPoint] ) 
        USING GEOGRAPHY_GRID 
        WITH 
        (     GRIDS=(LEVEL_1 = HIGH,LEVEL_2 = HIGH,LEVEL_3 = HIGH,LEVEL_4 = HIGH) 
                , CELLS_PER_OBJECT = 64 
                , PAD_INDEX = OFF 
                , SORT_IN_TEMPDB = OFF 
                , DROP_EXISTING = OFF 
                , ALLOW_ROW_LOCKS = ON 
                , ALLOW_PAGE_LOCKS = ON 
        ) 

        /*
            Find where locations from each table are within @Radius of each other
        */
        SELECT *
        FROM 
            #xLocation1 X
        INNER JOIN
            #xLocation2 P ON X.GeogPoint.STDistance(P.GeogPoint) <= @Radius

所有Lat Lng的sql表都在15公里内到每个不同的table-sql 2008的Lat lng

1 个答案: