Question

我有 JSON ，我希望将第一个对象的数据合并到第二个对象

{
    "ViewId": {
        "56": {
            "ViewId": "56",
            "Name": "hi",
            "param": "value"
        },
        "88": {
            "ViewId": "88",
            "Name": "hi2",
            "param": "value2"
        }
    },
    "que": [
        {
            "RId": "123",
            "ViewId": "88",
            "Count": 0
        },
        {
            "RId": "456",
            "ViewId": "56",
            "Count": 0
        }
    ]
}

基本上，我正在制作ArrayList，如何将ViewId数据添加到que中。我想以下列方式合并JSON：

{
    "que": [
        {
            "RId": "123",
            "ViewId": "88",
            "Name": "hi2",
            "param": "value2",
            "Count": 0
        },
        {
            "RId": "456",
            "ViewId": "56",
            "Name": "hi",
            "param": "value",
            "Count": 0
        }
    ]
}

Answer 1

    JSONObject ViewIdJsnObject = new JSONObject(); //replace new JSONObject() with ViewId Json Object here
    JSONArray queArray = new JSONArray();//replace new JSONArray() with actual json array;

    //Traverse through all que objects in array
    if(queArray != null && queArray.length() > 0){
        for(int i=0; i<queArray.length(); i++){
            try {
                JSONObject queObj = queArray.getJSONObject(i);
                String queViewId = queObj.getString("ViewId"); //ViewId of que object at position i
                JSONObject viewIdObj = ViewIdJsnObject.getJSONObject(queViewId); //get json object against ViewId
                if(viewIdObj != null) {
                    //Now add these value to que object at position i
                    String name = viewIdObj.getString("Name");
                    String param = viewIdObj.getString("param");
                    queObj.put("Name", name);
                    queObj.put("param", param);
                }
            } catch (JSONException jse) {
                jse.printStackTrace();
            }
        }
    }
    //Now que array contains final merged data, convert it to ArrayList<Your_model>.

Answer 2

制作课程

public class Data {
    int id;
    List<Que> que = new ArrayList<Que>();


    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }
    public List<Que> getQue() {
        return que;
    }
    public void setQue(List<Que> que) {
        this.que = que;
    }

}

创建另一个名为Que

的班级

public class Que {
    int RId;
    int ViewId;
    int Count;


    public int getrId() {
        return RId;
    }
    public void setrId(int rId) {
        this.RId = rId;
    }
    public int getViewId() {
        return ViewId;
    }
    public void setViewId(int viewId) {
        this.ViewId = viewId;
    }
    public int getCount() {
        return Count;
    }
    public void setCount(int count) {
        this.Count = count;
    }

}

使用gson

使用它

Gson gson = new Gson();
        Data data = gson.fromJson(json, Data.class);
        List<Que> queList = data.getQue();
        for(Que que : queList){
            System.out.println("This is R ID" +que.RId);
            System.out.println("This is View ID" +que.ViewId);
            System.out.println("This is Count" +que.Count);

确保您的json属性名称与java实例参数匹配。

结合json并制作arraylist <object>

2 个答案: