Question

我正在尝试在c编程中编写代码，提示人们回答布尔yes或no问题，然后相应地执行操作。而不是IF或switch。

include <stdlib.h>
include <stdio.h>

int main()
{
    int children;
    int age;

    printf("please enter your age");
    scanf("%d", age);


    printf("are you married?, please enter y for Yes and n for No"\n\n);
    scanf("%s", mstatus);

    if (mstatus is y or Y)
    {
        printf("how many children do you have: \n\n")
        scanf("%d", children)
    }

    return 0;
}

Answer 1

虽然您没有描述您所面临的具体问题，但我认为我可以提出以下意见：

首先，scanf()需要阅读指针才能正常工作。

您已声明：
```
int children;
int age;
```
因此您需要将scanf()语句修改为：
```
scanf("%d", &age);
```
和
```
scanf("%d", &children);
```
相应。
此外，您用来检查答案的条件也需要修改。将其更改为：
```
if (mstatus == 'y' || mstatus == 'Y')
```

此外，请更改以下行：

printf("are you married?, please enter y for Yes and n for No"\n\n);

到：

printf("are you married?, please enter y for Yes and n for No\n\n");

因为您不能在引号之外添加换行符。

最后，声明：

printf("how many children do you have: \n\n")
scanf("%d", children)

为了有效，

最后都需要一个分号，如下所示：

printf("how many children do you have: \n\n");
scanf("%d", children);

Answer 2

scanf("%d", age);

应该是：

scanf("%d", &age); // missing an ampersand here.

printf("are you married?, please enter y for Yes and n for No"\n\n);

到

printf("are you married?, please enter y for Yes and n for No\n\n"); // newlines should be inside the format string

虽然另一个答案解决了您的问题，但我相信使用switch-case会更好：

printf("are you married?, please enter y for Yes and n for No\n\n");
scanf("%c",&c);


switch(c)
{
 case('y'):
    printf("how many children do you have: \n\n");
    scanf("%d",&children); // Remember to put ampersand here
    break;
 case('n'):
    printf("Enjoy bachelorhood\n");
    break;
 default:
   printf("Choice neither y nor n, Confused about marriage?\n");
}

C编写布尔表达式

2 个答案: