我正在为python RPG创建一个商店/库存系统，并从我店里的一个函数返回几个变量。我每次访问商店时都会创建3-5个项目，所以如果您打印我的一个返回变量，它将打印最后一个项目的信息。我需要能够将每个唯一的项值存储在一个数组中，这样每个项目都可以被调用，而不仅仅是最后一个。
if plus == 0: #if item made has a plus equal to nothing
if has_add == 'yes': #if it has an add
if item_type == 'weapon': #if it is a weapon (no plus, has add, is weapon)
created_item = print(str(count) + ". " + quality + " " + wep_adj + " " + "" + weapon_type + " of " + wep_add + "..........Attack: " + str(weapon_attack) + " Price: " + str(wep_price)) #print this
if item_type == 'armor': #if it is an armor (no plus, has add, is armor)
created_item = print(str(count) + ". " + quality + " " + arm_adj + " " + " " + armor_piece + " of " + arm_add + "..........Armor: " + str(armor_defense) + " HP: " + str(armor_hp) + " Price: " + str(arm_price)) #print this
else: # if item doesnt have add
if item_type == 'weapon': #if it is a weapon (no plus, no add, is weapon)
created_item = print(str(count) + ". " + quality + " " + wep_adj + " " + "" + weapon_type + "..........Attack: " + str(weapon_attack) + " Price: " + str(wep_price)) #print this
if item_type == 'armor': # if it is an armor (no plus, no add, is armor)
created_item = print(str(count) + ". " + quality + " " + arm_adj + " " + " " + armor_piece + "..........Armor: " + str(armor_defense) + " HP: " + str(armor_hp) + " Price: " + str(arm_price)) #print this
else: #if item made has a plus
if has_add == 'yes': # if it has an add
if item_type == 'weapon': # if it is a weapon (has plus, has add, is weapon)
created_item = print(str(count) + ". " + quality + " " + wep_adj + " " + "" + weapon_type + " of " + wep_add + " +" + str(plus) + "..........Attack: " + str(weapon_attack) + " Price: " + str(wep_price)) #print this
if item_type == 'armor': #if it is an armor (has plus, has add, is armor)
created_item = print(str(count) + ". " + quality + " " + arm_adj + " " + " " + armor_piece + " of " + arm_add + " +" + str(plus) + "..........Armor: " + str(armor_defense) + " HP: " + str(armor_hp) + " Price: " + str(arm_price)) #print this
else: # if it doesnt have an add
if item_type == 'weapon': #if it is a weapon (has plus, no add, is weapon)
created_item = print(str(count) + ". " + quality + " " + wep_adj + " " + "" + weapon_type + " +" + str(plus) + "..........Attack: " + str(weapon_attack) + " Price: " + str(wep_price)) #print this
if item_type == 'armor': #if it is an armor (has plus, no add, is armor)
created_item = print(str(count) + ". " + quality + " " + arm_adj + " " + " " + armor_piece + " +" + str(plus) + "..........Armor: " + str(armor_defense) + " HP: " + str(armor_hp) + " Price: " + str(arm_price)) #print this
if item_type == 'weapon': #allows us to get info out of function
return (created_item, count, quality, wep_adj, weapon_type, wep_add, plus, weapon_attack, wep_price, randvar)
else:
return (created_item, count, quality, arm_adj, armor_piece, arm_add, plus, armor_defense, arm_price, armor_hp)
while items_amount > items_made: #if we've made 3-5 items, stop making them
new_item, count, quality, adj, piece, add, plus, stat, price, other_stat = make_item()
items_made += 1 #increase items made every time one is made
count += 1
return (new_item, count, quality, adj, piece, add, plus, stat, price, other_stat)
new_item, count, quality, adj, piece, add, plus, stat, price, other_stat = generate_items() #call function to make all items when shop is visited
print(new_item, count, quality, adj, piece, add, plus, stat, price, other_stat)
由于我的代码非常庞大，我不想链接整个相关代码。最相关的是：
while items_amount > items_made: #if we've made 3-5 items, stop making them
new_item, count, quality, adj, piece, add, plus, stat, price, other_stat = make_item()
items_made += 1 #increase items made every time one is made
count += 1
return (new_item, count, quality, adj, piece, add, plus, stat, price, other_stat)
我需要能够将它们作为数组而不是变量
返回答案 0 :(得分：2)
您可以将您要归还的内容视为一个tuple变量并将其附加到list：
items = list()
while items_amount > items_made: # if we've made 3-5 items, stop making them
new_item_details = make_item() # assign to one tuple variable
items.append(new_item_details) # append to list
items_made += 1 # increase items made every time one is made
count += 1
return items
如果您想访问单个item的每个细节，并且您希望它也很好，我建议您创建一个包含所需变量的类：
class Item(object):
def __init__(self, item_details):
self.item = item_details[0]
self.count = item_details[1]
self.quality = item_details[2]
self.adj = item_details[3]
... # similarily other fields
self.other_stat = item_details[9]
然后你可以创建这些项目：
items = list()
while items_amount > items_made: # if we've made 3-5 items, stop making them
new_item_details = make_item() # assign to one tuple variable
items.append(Item(new_item_details)) # append to list
items_made += 1 # increase items made every time one is made
count += 1
return items
现在，如果您想访问第二项的adj：
# 1st index would be the second item in the list
items[1].adj # access using variable name on the instance
答案 1 :(得分：1)
将元组插入列表：
items = list()
while items_amount > items_made: # if we've made 3-5 items, stop making them
new_item, count, quality, adj, piece, add, plus, stat, price, other_stat = make_item()
items_made += 1 # increase items made every time one is made
count += 1
items.append((new_item, count, quality, adj, piece, add, plus, stat, price, other_stat))
return items