我要做的是编写一个打开带有电影评论的.txt文件的程序，其中评级为0-4之间的数字，然后是电影的简短评论。然后，程序提示用户打开第二个文本文件，其中包含将与评论匹配的单词，并根据评论给出一个数字值。
例如，通过这两个示例评论它们将如何显示在.txt文件中：
4这是一部近乎史诗般的喜剧剧，其根源在于正在经历中年危机的头衔。 2马苏德的故事是一部史诗般的故事，也是一部悲剧，是一位顽强，人道的战士，也是囚犯-LRB-并最终成为历史的受害者-RRB-的记录。所以，如果我正在寻找单词＆＃34; epic＆＃34;，它会将该单词的计数增加2（我已经想到了），因为它出现了两次，然后追加值4和2到该单词的评级列表。
如何将这些内容附加到与该单词相关的列表或词典中？请记住，我需要为单词列表中的每个单词创建一个新列表或dicitonary key。
请谢谢。对不起，如果措辞不好，编程就不是我的强项。
我的所有代码：
def menu_validate(prompt, min_val, max_val):
""" produces a prompt, gets input, validates the input and returns a value. """
while True:
try:
menu = int(input(prompt))
if menu >= min_val and menu <= max_val:
return menu
break
elif menu.lower == "quit" or menu.lower == "q":
quit()
print("You must enter a number value from {} to {}.".format(min_val, max_val))
except ValueError:
print("You must enter a number value from {} to {}.".format(min_val, max_val))
def open_file(prompt):
""" opens a file """
while True:
try:
file_name = str(input(prompt))
if ".txt" in file_name:
input_file = open(file_name, 'r')
return input_file
else:
input_file = open(file_name+".txt", 'r')
return input_file
except FileNotFoundError:
print("You must enter a valid file name. Make sure the file you would like to open is in this programs root folder.")
def make_list(file):
lst = []
for line in file:
lst2 = line.split(' ')
del lst2[-1]
lst.append(lst2)
return lst
def rating_list(lst):
'''iterates through a list of lists and appends the first value in each list to a second list'''
rating_list = []
for list in lst:
rating_list.append(list[0])
return rating_list
def word_cnt(lst, word : str):
cnt = 0
for list in lst:
for word in list:
cnt += 1
return cnt
def words_list(file):
lst = []
for word in file:
lst.append(word)
return lst
##def sort(words, occurrences, avg_scores, std_dev):
## '''sorts and prints the output'''
## menu = menu_validate("You must choose one of the valid choices of 1, 2, 3, 4 \n Sort Options\n 1. Sort by Avg Ascending\n 2. Sort by Avg Descending\n 3. Sort by Std Deviation Ascending\n 4. Sort by Std Deviation Descending", 1, 4)
## print ("{}{}{}{}\n{}".format("Word", "Occurence", "Avg. Score", "Std. Dev.", "="*51))
## if menu == 1:
## for i in range (len(word_list)):
## print ("{}{}{}{}".format(cnt_list.sorted[i],)
def make_odict(lst1, lst2):
'''makes an ordered dictionary of keys/values from 2 lists of equal length'''
dic = OrderedDict()
for i in range (len(word_list)):
dic[lst2[i]] = lst2[i]
return dic
cnt_list = []
while True:
menu = menu_validate("1. Get sentiment for all words in a file? \nQ. Quit \n", 1, 1)
if menu == True:
ratings_file = open("sample.txt")
ratings_list = make_list(ratings_file)
word_file = open_file("Enter the name of the file with words to score \n")
word_list = words_list(word_file)
for word in word_list:
cnt = word_cnt(ratings_list, word)
cnt_list.append(word_cnt(ratings_list, word))
对不起，我知道它很乱，而且非常不完整。
答案 0 :(得分：1)
我认为你的意思是：
import collections
counts = collections.defaultdict(int)
word = 'epic'
counts[word] += 1
显然，你可以使用word做比我更多的事情，但你没有向我们展示任何代码，所以......
修改
好的，看看你的代码，我建议你将评级和文字分开。拿这个：
def make_list(file):
lst = []
for line in file:
lst2 = line.split(' ')
del lst2[-1]
lst.append(lst2)
return lst
并将其转换为：
def parse_ratings(file):
"""
Given a file of lines, each with a numeric rating at the start,
parse the lines into score/text tuples, one per line. Return the
list of parsed tuples.
"""
ratings = []
for line in file:
text = line.strip().split()
if text:
score = text[0]
ratings.append((score,text[1:]))
return ratings
然后你可以一起计算两个值：
def match_reviews(word, ratings):
cnt = 0
scores = []
for score,text in ratings:
n = text.count(word)
if n:
cnt += n
scores.append(score)
return (cnt, scores)