Question

因此该程序假设采用“yyyy / dd / mm”格式的日期。在每个日期之后，可以输入文本。例如，“1776/7/4第一独立日”。我想使用一个String tokenizer并在斜杠上分割日期，但后来我很困惑如何在那之后将它拆分。一旦我拆分它们，我可以将日期与其他日期进行比较吗？

    Scanner sc = new Scanner(System.in);
    System.out.print("Enter the first date: ");
    String firstDate = sc.nextLine();
    //System.out.print("Enter the second date: ");
    //String secondDate = sc.nextLine();
    //System.out.println();
    //StringTokenizer date = new StringTokenizer(firstDate, "/",false);
    //StringTokenizer space = new StringTokenizer(firstDate, " ",false);
    //if (firstDate.equals(secondDate))
    //{
     //   System.out.println (
       //         "There are 0 year(s), 0 month(s) and 0 day(s) between dates");
    //}
    int firstSpace = firstDate.indexOf(' ');

    String event = firstDate.substring(firstSpace + 1);    // "First Independence Day"

    String date = firstDate.substring(0, firstSpace);    // "1776/7/4"

    // split on '/'
    String dateParts[] = date.split("/");
    String dateParts1[] = date.split("/");
    String dateParts2[]= date.split("/");
    if(dateParts1[1].length() != 2)
        dateParts1[1] = "0" + dateParts1[1];

    // add 0 to front of day
    if(dateParts1[2].length() != 2)
        dateParts1[2] = "0" + dateParts1[2];

    // do the same for the second date
    if(dateParts2[1].length() != 2)
        dateParts2[1] = "0" + dateParts2[1];

    // convert array to string
    String date1 = String.join("/", dateParts1);
    String date2 = String.join("/", dateParts2);

    // set up the format that you have
    SimpleDateFormat dateFormat = new SimpleDateFormat ("yyyy/MM/dd");

    Date d1 = dateFormat.parse(date1);
    Date d2 = dateFormat.parse(date2);

    // equal dates
    if(d1.equals(d2)) {
        // There or 0 days, months and years between dates.
    }

Answer 1

String x = "yyyy/dd/mm";
String[] split = x.split("/");
for (String s : split) {
    System.out.println(s);
}


Output:
yyyy
dd
mm

Answer 2

我认为获取第一个空格字符的索引是个好主意。

String text = "1776/7/4 First Independence Day";
                       ^

int firstSpace = text.indexOf(' ');

String event = text.substring(firstSpace + 1);    // "First Independence Day"

String date = text.substring(0, firstSpace);    // "1776/7/4"

// split on '/'
String dateParts[] = date.split("/");

即使事件名称包含/，这也将确保一切正常。

修改

要比较日期，首先需要确保像April这样的月份的值为04而不是4.假设您有2个数组，dateParts1和dateParts2。

// add 0 to front of month if(dateParts1[1].length() != 2) dateParts1[1] = "0" + dateParts1[1]; // add 0 to front of day if(dateParts1[2].length() != 2) dateParts1[2] = "0" + dateParts1[2]; // do the same for the second date; // convert array to string String date1 = String.join("/", dateParts1); String date2 = String.join("/", dateParts2); // set up the format that you have SimpleDateFormat dateFormat = new SimpleDateFormat ("yyyy/MM/dd"); Date d1 = dateFormat.parse(date1); Date d2 = dateFormat.parse(date2); // equal dates if(d1.equals(d2)) { // do something } if(date2.after(date1)) return true; else return false;

编辑2 。

String firstDate = "1776/7/4 First Independence Day"; int firstSpace = firstDate.indexOf(' '); String event = firstDate.substring(firstSpace + 1); // "First Independence Day" String date = firstDate.substring(0, firstSpace); // "1776/7/4" String dateParts1[] = date.split("/"); String dateParts2[] = date.split("/"); // add 0 to front of month if (dateParts1[1].length() != 2) dateParts1[1] = "0" + dateParts1[1]; // add 0 to front of day if (dateParts1[2].length() != 2) dateParts1[2] = "0" + dateParts1[2]; // do the same for the second date if (dateParts2[1].length() != 2) dateParts2[1] = "0" + dateParts2[1]; // add 0 to front of day if (dateParts2[2].length() != 2) dateParts2[2] = "0" + dateParts2[2]; // convert array to string String date1 = String.join("/", dateParts1); String date2 = String.join("/", dateParts2); // set up the format that you have java.text.SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy/MM/dd"); java.util.Date d1 = dateFormat.parse(date1); java.util.Date d2 = dateFormat.parse(date2); if (d1.equals(d2)) System.out.println("equal");

Answer 3

我建议使用正则表达式和DateFormat ...

String input = "1776/07/04 First Independence Day";
Pattern pattern = Pattern.compile("(\\d+/\\d+/\\d+)\\s+(.*)");
Matcher matcher = pattern.matcher(input);
if (matcher.find()) {
    DateFormat format = new SimpleDateFormat("yyyy/M/d");
    Date date = format.parse(matcher.group(1));
    System.out.println(date + " " + matcher.group(2));
}

Answer 4

我不太明白你的问题。你可以把第一个令牌作为日期并将其保存在一个新的字符串中，然后你可以简单地使用string.compareTo（另一个字符串）进行比较;或者您可以使用简单的scanner.nextInt（）：方法将年，月和日作为整数，然后比较它们！希望我帮忙。

Answer 5

只需像这样使用splite

字符串数据;

string [] parts;

parts = data.splite（＆＃39;＆＃39;）;

拆分用户在Java中输入日期

5 个答案: