Question

我有一个遵循{ name: "John" }而不是{ "name" : "John"}格式的JSON字符串，每当我尝试访问名称密钥时都会产生nil，因为：

Error Domain=NSCocoaErrorDomain Code=3840 "No string key for value in object around character 1."

我正在寻找一个修复/解析/格式化这个JSON文件的函数？像JSON Format这样的网站如何做到这一点？

Answer 1

有趣的是，{ name: "John" }在Javascript中生成了一个有效的JSON对象。所以你现在的问题就是为Swift找到一个Javascript解释器！

最近版本的Mac OS X和iOS内置了一个：WKWebView。它是一个带有Javascript解析器的Web呈现引擎。将您的目标与WebKit链接并尝试：

import WebKit

class MyJSONParser {
    private static let webView = WKWebView()

    class func parse(jsonString: String, completionHandler: (AnyObject?, NSError?) -> Void) {
        self.webView.evaluateJavaScript(jsonString, completionHandler: completionHandler)
    }
}

用法：

let str = "{ firstName: 'John', lastName: 'Smith' }"

// You must assign the JSON string to a variable or the Javascript
// will return void. Note that this runs asynchronously
MyJSONParser.parse("tmp = \(str)") { result, error in
    guard error == nil else {
        print(error)
        return
    }
    if let dict = result as? [String: String] {
        print(dict)
    } else {
       print("Can't convert to Dictionary")
    }
}

Swift 3

import WebKit
class MyJSONParser {
    private static let webView = WKWebView()

    class func parse(jsonString: String, completionHandler: @escaping (Any?, Error?) -> Void) {
        self.webView.evaluateJavaScript(jsonString, completionHandler: completionHandler)
    }
}

let str = "{ firstName: 'John', lastName: 'Smith' }"

// You must assign the JSON string to a variable or the Javascript
// will return void. Note that this runs asynchronously
MyJSONParser.parse(jsonString: "tmp = \(str)") { result, error in
    guard error == nil else {
        print(error!)
        return
    }
    if let dict = result as? [String: String] {
        print(dict)
    } else {
        print("Can't convert to Dictionary")
    }
}

如何在Swift中格式化JSON字符串？

1 个答案:

Swift 3